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The homework asks you to solve two equations: 

1. \( x^2 = 121 \)
2. \( x^2 = 64 \)

### Solution for \( x^2 = 121 \):
To solve for \( x \), take the square root of both sides:
\[
x = \pm \sqrt{121}
\]
\[
x = \pm 11
\]
So, the solutions are \( x = 11 \) and \( x = -11 \).

### Solution for \( x^2 = 64 \):
Similarly, take the square root of both sides:
\[
x = \pm \sqrt{64}
\]
\[
x = \pm 8
\]
So, the solutions are \( x = 8 \) and \( x = -8 \).

Would you like further details on the method or have any additional questions?

Here are some related questions to explore:
1. What is the general method for solving quadratic equations like \( x^2 = c \)?
2. How do we know when to include both positive and negative solutions?
3. Can you solve equations like \( x^2 = -49 \)? Why or why not?
4. What happens if the equation is \( x^2 = 0 \)?
5. How can you apply this technique to more complex equations?

**Tip**: Always remember that for equations involving squares, there are typically two solutions—one positive and one negative—unless the equation equals zero.

Learn how to solve quadratic equations like x^2 = 121 and x^2 = 64 by using the square root method. Understand why the solutions include both positive and negative values. Suitable for students in Grades 6-8.

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