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The equation provided is:

\[
m^2 = 49
\]

To solve for \( m \), take the square root of both sides of the equation:

\[
m = \pm \sqrt{49}
\]

\[
m = \pm 7
\]

Thus, the solution is:

\[
m = 7 \quad \text{or} \quad m = -7
\]

Would you like further details on how to handle square root equations or any other follow-up questions?

Here are some related questions you might find useful:

1. What is the square root of a negative number?
2. How do you solve equations of the form \(m^2 = k\) when \(k\) is not a perfect square?
3. What are the properties of square roots that make them useful in solving equations?
4. Can square roots be simplified for non-integer results?
5. How does the quadratic formula handle square roots?

**Tip:** Always consider both the positive and negative roots when solving square equations like \(m^2 = 49\).

Learn how to solve the equation m^2 = 49 by applying square root principles. This algebraic problem demonstrates key concepts like square roots and the solution to quadratic-like equations. Suitable for students in Grades 6-8.

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