To solve the system of equations:

1. \( y = -2x \)
2. \( x + y = -1 \)

We can use substitution or elimination. Here, we'll use substitution because \( y \) is already expressed in terms of \( x \).

Substitute \( y = -2x \) into the second equation:

\[ x + (-2x) = -1 \]
\[ x - 2x = -1 \]
\[ -x = -1 \]
\[ x = 1 \]

Now, substitute \( x = 1 \) back into the first equation to find \( y \):

\[ y = -2(1) \]
\[ y = -2 \]

So, the solution to the system of equations is:

\[ x = 1 \]
\[ y = -2 \]

Would you like more details on the solution or have any questions?

Here are 5 questions you can ask next:
1. How do you solve a system of equations using the elimination method?
2. Can you explain how to graph the equations \( y = -2x \) and \( x + y = -1 \)?
3. What are the steps to solve a system of equations using matrices?
4. How can we check if a system of equations has no solution or infinitely many solutions?
5. Can you explain how to solve nonlinear systems of equations?

**Tip:** When solving systems of equations, always check if substitution or elimination is more straightforward based on how the equations are presented.

Learn how to solve the system of equations y = -2x and x + y = -1 using the substitution method. Step-by-step solution provided with detailed calculations. Suitable for high school students.

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