Math Problem Statement

-x + y = -2, 3x + y = 2. First equation solved in the form y = ?. What is the solution (x, y)?

Solution

I can see the system of equations from the uploaded image:

x+y=2(1)-x + y = -2 \quad \text{(1)} 3x+y=2(2)3x + y = 2 \quad \text{(2)}

Step 1: Solve the first equation for yy

From equation (1): x+y=2-x + y = -2 Add xx to both sides: y=x2y = x - 2

Step 2: Substitute into the second equation

Now, substitute y=x2y = x - 2 into the second equation 3x+y=23x + y = 2: 3x+(x2)=23x + (x - 2) = 2 Simplify: 3x+x2=23x + x - 2 = 2 4x2=24x - 2 = 2 Add 2 to both sides: 4x=44x = 4 Divide by 4: x=1x = 1

Step 3: Find yy

Now that x=1x = 1, substitute it back into y=x2y = x - 2: y=12=1y = 1 - 2 = -1

Solution:

The solution to the system of equations is: (x,y)=(1,1)(x, y) = (1, -1)

Would you like any further details or clarifications?

Here are 5 related questions to consider:

  1. How can we verify the solution of a system of equations?
  2. What are the different methods to solve a system of linear equations?
  3. Can all systems of linear equations have unique solutions?
  4. How does graphing help in solving a system of equations?
  5. What does it mean when a system of equations has no solution or infinitely many solutions?

Tip: Substitution is often a simpler method when one equation is already solved for a variable.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
System of Equations

Formulas

y = x - 2
Substitution Method

Theorems

The substitution method for solving systems of linear equations

Suitable Grade Level

Grades 8-10