Math Problem Statement

Solution

Let's solve the two given limit problems step by step.

Problem 1

limx+x(x2+1x)\lim_{x \to +\infty} x (\sqrt{x^2 + 1 - x})

Solution:

First, simplify the expression inside the square root:

x2+1x\sqrt{x^2 + 1 - x}

As x+x \to +\infty, the term x2x^2 dominates the expression inside the square root. So, we can approximate:

x2+1xx2x=x11xx(112x)=x12\sqrt{x^2 + 1 - x} \approx \sqrt{x^2 - x} = x\sqrt{1 - \frac{1}{x}} \approx x\left(1 - \frac{1}{2x}\right) = x - \frac{1}{2}

Thus, the expression becomes:

x(x12)=x2x2x \left(x - \frac{1}{2}\right) = x^2 - \frac{x}{2}

Taking the limit as x+x \to +\infty:

limx+(x2x2)=\lim_{x \to +\infty} (x^2 - \frac{x}{2}) = \infty

So, the answer for the first limit is: \infty

Problem 2

limx+(2x+32x+1)x+1\lim_{x \to +\infty} \left(\frac{2x + 3}{2x + 1}\right)^{x + 1}

Solution:

First, analyze the base of the exponent:

2x+32x+1=2x(1+32x)2x(1+12x)=1+32x1+12x\frac{2x + 3}{2x + 1} = \frac{2x (1 + \frac{3}{2x})}{2x (1 + \frac{1}{2x})} = \frac{1 + \frac{3}{2x}}{1 + \frac{1}{2x}}

As x+x \to +\infty, both 32x\frac{3}{2x} and 12x\frac{1}{2x} approach 0:

1+32x1+12x1\frac{1 + \frac{3}{2x}}{1 + \frac{1}{2x}} \to 1

However, this expression converges to 1. To evaluate the limit, consider the expression in the form suitable for applying the exponential limit:

(2x+32x+1)x+1\left(\frac{2x + 3}{2x + 1}\right)^{x + 1}

Let y=(2x+32x+1)x+1y = \left(\frac{2x + 3}{2x + 1}\right)^{x + 1}. Taking the natural logarithm on both sides:

lny=(x+1)ln(2x+32x+1)\ln y = (x + 1) \ln \left(\frac{2x + 3}{2x + 1}\right)

Using the approximation for small hh where ln(1+h)h\ln(1 + h) \approx h:

ln(2x+32x+1)ln(1+22x+1)22x+1\ln \left(\frac{2x + 3}{2x + 1}\right) \approx \ln \left(1 + \frac{2}{2x + 1}\right) \approx \frac{2}{2x + 1}

Thus,

lny(x+1)22x+1\ln y \approx (x + 1) \cdot \frac{2}{2x + 1}

For large xx:

x+12x+1x2x=12\frac{x + 1}{2x + 1} \approx \frac{x}{2x} = \frac{1}{2}

So,

lny212=1\ln y \approx 2 \cdot \frac{1}{2} = 1

Hence,

yey \approx e

Therefore, the limit for the second problem is: ee

Summary of Answers:

  1. \infty
  2. ee

Would you like more details or have any questions about these solutions?

Here are some additional questions you might consider:

  1. How do you evaluate limits involving indeterminate forms?
  2. What techniques can be used to simplify complex expressions inside limits?
  3. How do exponential limits with bases approaching 1 behave?
  4. What are some common approximations used in limit calculations?
  5. How can you apply the natural logarithm to simplify limit problems?

Tip: When solving limits at infinity, always consider the dominant terms in the expressions to simplify your calculations.

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Math Problem Analysis

Mathematical Concepts

Limits
Exponential Functions
Asymptotic Analysis

Formulas

Limit definition
Exponential limit approximation

Theorems

Limit properties
Exponential limit rules

Suitable Grade Level

Advanced High School