Math Problem Statement

If d/dx (f(x)) = 2x + 3/x and f(1) = 1 then f(x) is

Solution

To find f(x)f(x), we need to integrate the given derivative ddxf(x)=2x+3x\frac{d}{dx} f(x) = 2x + \frac{3}{x}.

First, we integrate each term separately: (2x+3x)dx\int (2x + \frac{3}{x}) \, dx

  1. Integrate 2x2x: 2xdx=x2+C1\int 2x \, dx = x^2 + C_1

  2. Integrate 3x\frac{3}{x}: 3xdx=3lnx+C2\int \frac{3}{x} \, dx = 3 \ln |x| + C_2

Combining these results, we get: f(x)=x2+3lnx+Cf(x) = x^2 + 3 \ln |x| + C

Now, we use the initial condition f(1)=1f(1) = 1 to find the constant CC: f(1)=12+3ln1+C=1+0+C=1f(1) = 1^2 + 3 \ln |1| + C = 1 + 0 + C = 1 C=0C = 0

Therefore, the function f(x)f(x) is: f(x)=x2+3lnxf(x) = x^2 + 3 \ln |x|

Do you want more details or have any questions? Here are 5 related questions you can ask:

  1. How do you integrate 2x2x step-by-step?
  2. Why is lnx\ln |x| used instead of lnx\ln x?
  3. What are the properties of the natural logarithm function?
  4. Can you explain how to use initial conditions to find constants in integrals?
  5. What are the rules for integration of basic functions?

Tip: Always check initial conditions carefully to ensure the correct determination of constants in indefinite integrals.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Integration
Initial Value Problem

Formulas

Fundamental Theorem of Calculus

Theorems

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Suitable Grade Level

Advanced High School or Early College