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The system of equations you provided is:

\[
1) \ 5x + 4y = 14
\]
\[
2) \ y = 2x - 3
\]

To solve this using substitution:

### Step 1: Substitute \( y = 2x - 3 \) into the first equation

Substitute the expression for \( y \) from the second equation into the first equation:

\[
5x + 4(2x - 3) = 14
\]

### Step 2: Simplify the equation

Now, expand and simplify:

\[
5x + 8x - 12 = 14
\]
\[
13x - 12 = 14
\]

### Step 3: Solve for \( x \)

Add 12 to both sides:

\[
13x = 26
\]

Now, divide by 13:

\[
x = 2
\]

### Step 4: Solve for \( y \)

Now that we know \( x = 2 \), substitute this value back into the second equation \( y = 2x - 3 \):

\[
y = 2(2) - 3 = 4 - 3 = 1
\]

### Solution:

\[
x = 2, \ y = 1
\]

Would you like more details or have any questions?

Here are 5 related questions to expand this topic:
1. Can substitution be used for all systems of linear equations?
2. How can you verify the solution to a system of equations?
3. What other methods can solve systems of linear equations (e.g., elimination)?
4. What happens if the system of equations has no solution or infinitely many solutions?
5. How would you solve this system graphically?

**Tip:** Always substitute your solution back into the original equations to verify it satisfies both equations.

Solve the system of equations: 5x + 4y = 14 and 2x - 3 = y using substitution.

Learn how to solve a system of linear equations using substitution, where 5x + 4y = 14 and y = 2x - 3. This step-by-step guide is suitable for students in Grades 8-10, covering key algebra concepts and substitution techniques.

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