Math Problem Statement

A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 0.7 ft/s, how fast (in rad/s) is the angle (in radians) between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall? (That is, find the angle's rate of change when the bottom of the ladder is 8 ft from the wall.)

Solution

Given:

  • Ladder length L=10L = 10 ft (constant)
  • Rate at which the bottom of the ladder slides away from the wall dxdt=0.7\frac{dx}{dt} = 0.7 ft/s
  • Distance of the bottom of the ladder from the wall at the specific moment x=8x = 8 ft

We need to find:

  • The rate at which the angle θ\theta between the ladder and the ground is changing, dθdt\frac{d\theta}{dt}, in radians per second.

First, we apply the Pythagorean theorem to relate the height yy of the ladder on the wall to the distance xx from the wall:

x2+y2=L2x^2 + y^2 = L^2

Given L=10L = 10 ft,

82+y2=102    64+y2=100    y2=36    y=6 ft8^2 + y^2 = 10^2 \implies 64 + y^2 = 100 \implies y^2 = 36 \implies y = 6 \text{ ft}

To find the rate at which θ\theta is changing, we use trigonometric relationships. Specifically, cos(θ)\cos(\theta) is given by:

cos(θ)=xL\cos(\theta) = \frac{x}{L}

Taking the derivative with respect to time tt:

[ \frac{d}{dt} [ \cos(\theta) ] = \frac{d}{dt} \left[ \frac{x}{L} \right] ]

Since LL is constant,

sin(θ)dθdt=1Ldxdt-\sin(\theta) \frac{d\theta}{dt} = \frac{1}{L} \frac{dx}{dt}

Solving for dθdt\frac{d\theta}{dt},

dθdt=1Lsin(θ)dxdt\frac{d\theta}{dt} = -\frac{1}{L \sin(\theta)} \frac{dx}{dt}

We already know L=10L = 10 ft and dxdt=0.7\frac{dx}{dt} = 0.7 ft/s. To find sin(θ)\sin(\theta), use:

sin(θ)=yL=610=0.6\sin(\theta) = \frac{y}{L} = \frac{6}{10} = 0.6

Substitute the values into the equation:

dθdt=110×0.6×0.7=0.76=760 rad/s\frac{d\theta}{dt} = -\frac{1}{10 \times 0.6} \times 0.7 = -\frac{0.7}{6} = -\frac{7}{60} \text{ rad/s}

Therefore, the rate at which the angle is changing is:

dθdt=760 rad/s\frac{d\theta}{dt} = -\frac{7}{60} \text{ rad/s}

This negative sign indicates that the angle is decreasing.

Would you like more details or have any questions?

Here are some related questions:

  1. How is the Pythagorean theorem used to solve related rates problems?
  2. What is the relationship between the rates of change of the sides of a right triangle and its angles?
  3. How can trigonometric identities help in solving related rates problems?
  4. What is the significance of the negative sign in the rate of change of the angle?
  5. How does the rate of change of the distance of the ladder's bottom from the wall affect the rate of change of the angle?
  6. How do you differentiate trigonometric functions with respect to time?
  7. What are some other common real-life applications of related rates problems?
  8. How does the length of the ladder influence the rate at which the angle changes?

Tip: Always draw a diagram when solving related rates problems to visualize the relationship between the different quantities and their rates of change.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometry
Related Rates

Formulas

Pythagorean theorem
Trigonometric identities

Theorems

-

Suitable Grade Level

High School