Math Problem Statement

x²-(p-2)x-6=0 has roots of my and n, where m²+2mn+n²=9, find the value of p

Solution

We are given the quadratic equation:

x2(p2)x6=0x^2 - (p - 2)x - 6 = 0

The roots of this equation are mm and nn, and we are also given that m2+2mn+n2=9m^2 + 2mn + n^2 = 9. Let's solve for pp.

Step 1: Use Vieta's Formulas

From Vieta's formulas, for a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum and product of the roots are given by: m+n=ba,mn=ca.m + n = -\frac{b}{a}, \quad mn = \frac{c}{a}. For our equation x2(p2)x6=0x^2 - (p - 2)x - 6 = 0, we have:

  • Sum of roots: m+n=p2m + n = p - 2,
  • Product of roots: mn=6mn = -6.

Step 2: Use the given condition

We are also given the condition: m2+2mn+n2=9.m^2 + 2mn + n^2 = 9. We can rewrite this as: (m+n)2=m2+2mn+n2=9.(m + n)^2 = m^2 + 2mn + n^2 = 9.

Step 3: Substitute the sum and product of the roots

We already know:

  • m+n=p2m + n = p - 2,
  • mn=6mn = -6.

Substitute m+n=p2m + n = p - 2 into (m+n)2=9(m + n)^2 = 9: (p2)2=9.(p - 2)^2 = 9.

Step 4: Solve for pp

Expand the equation: (p2)2=9p2=±3.(p - 2)^2 = 9 \quad \Rightarrow \quad p - 2 = \pm 3. This gives two possible solutions:

  1. p2=3p=5p - 2 = 3 \quad \Rightarrow \quad p = 5,
  2. p2=3p=1p - 2 = -3 \quad \Rightarrow \quad p = -1.

Step 5: Verify the solutions

We need to check both solutions with the condition mn=6mn = -6.

For p=5p = 5:

  • m+n=52=3m + n = 5 - 2 = 3.
  • Solve the quadratic equation t23t6=0t^2 - 3t - 6 = 0, and the discriminant is Δ=9+24=33\Delta = 9 + 24 = 33, which yields real roots, so p=5p = 5 is valid.

For p=1p = -1:

  • m+n=12=3m + n = -1 - 2 = -3.
  • Solve the quadratic equation t2+3t6=0t^2 + 3t - 6 = 0, and the discriminant is also 3333, which also yields real roots, so p=1p = -1 is also valid.

Conclusion:

The possible values of pp are 55 and 1-1.

Would you like more details or have any questions?

Here are 5 related questions:

  1. How does Vieta's formulas apply to general quadratic equations?
  2. How do you solve quadratic equations using the discriminant?
  3. What are the possible cases when m2+2mn+n2=9m^2 + 2mn + n^2 = 9?
  4. How does the discriminant help determine the nature of roots?
  5. What other techniques can be used to verify the roots of a quadratic equation?

Tip: Always check your solutions by substituting them back into the original equation or conditions to ensure they satisfy all given constraints.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Vieta's Formulas

Formulas

Sum of roots: m + n = -(b/a)
Product of roots: mn = c/a
(m + n)^2 = m^2 + 2mn + n^2

Theorems

Vieta's Formulas
Discriminant

Suitable Grade Level

Grades 9-11