Math Problem Statement
x²-(p-2)x-6=0 has roots of my and n, where m²+2mn+n²=9, find the value of p
Solution
We are given the quadratic equation:
The roots of this equation are and , and we are also given that . Let's solve for .
Step 1: Use Vieta's Formulas
From Vieta's formulas, for a quadratic equation , the sum and product of the roots are given by: For our equation , we have:
- Sum of roots: ,
- Product of roots: .
Step 2: Use the given condition
We are also given the condition: We can rewrite this as:
Step 3: Substitute the sum and product of the roots
We already know:
- ,
- .
Substitute into :
Step 4: Solve for
Expand the equation: This gives two possible solutions:
- ,
- .
Step 5: Verify the solutions
We need to check both solutions with the condition .
For :
- .
- Solve the quadratic equation , and the discriminant is , which yields real roots, so is valid.
For :
- .
- Solve the quadratic equation , and the discriminant is also , which also yields real roots, so is also valid.
Conclusion:
The possible values of are and .
Would you like more details or have any questions?
Here are 5 related questions:
- How does Vieta's formulas apply to general quadratic equations?
- How do you solve quadratic equations using the discriminant?
- What are the possible cases when ?
- How does the discriminant help determine the nature of roots?
- What other techniques can be used to verify the roots of a quadratic equation?
Tip: Always check your solutions by substituting them back into the original equation or conditions to ensure they satisfy all given constraints.
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Equations
Vieta's Formulas
Formulas
Sum of roots: m + n = -(b/a)
Product of roots: mn = c/a
(m + n)^2 = m^2 + 2mn + n^2
Theorems
Vieta's Formulas
Discriminant
Suitable Grade Level
Grades 9-11
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