To solve the equation \( \frac{20}{3} = \frac{N}{60} \), we can cross-multiply to eliminate the fractions.

\[
20 \times 60 = 3 \times N
\]

This simplifies to:

\[
1200 = 3N
\]

Next, divide both sides by 3 to solve for \( N \):

\[
N = \frac{1200}{3} = 400
\]

So, \( N = 400 \).

Would you like more details or have any questions?

Here are 5 related questions for practice:
1. Solve for \( N \) in the equation \( \frac{15}{4} = \frac{N}{20} \).
2. If \( \frac{7}{5} = \frac{N}{35} \), what is \( N \)?
3. Solve \( \frac{8}{N} = \frac{16}{20} \) for \( N \).
4. What is the value of \( N \) if \( \frac{25}{N} = \frac{5}{4} \)?
5. Find \( N \) when \( \frac{N}{9} = \frac{10}{3} \).

**Tip:** When working with proportions, cross-multiplication is a powerful method to solve for unknown variables quickly.

Learn how to solve the proportion 20/3 = N/60 step-by-step with detailed explanation and practice questions. This problem involves proportions and cross-multiplication method. Suitable for students in Grades 6-8.

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