Math Problem Statement

Y-2=1/5(x+5)

Solution

To solve the equation Y2=15(x+5)Y - 2 = \frac{1}{5}(x + 5), follow these steps:

Step 1: Isolate YY

We want to solve for YY. Start by simplifying the right-hand side of the equation.

Y2=15(x+5)Y - 2 = \frac{1}{5}(x + 5)

Distribute 15\frac{1}{5} to both terms inside the parentheses:

Y2=15x+1Y - 2 = \frac{1}{5}x + 1

Step 2: Solve for YY

Now, add 2 to both sides to isolate YY:

Y=15x+1+2Y = \frac{1}{5}x + 1 + 2

Simplify the right-hand side:

Y=15x+3Y = \frac{1}{5}x + 3

So, the final equation is:

Y=15x+3Y = \frac{1}{5}x + 3

This is the solution in slope-intercept form Y=mx+bY = mx + b, where the slope m=15m = \frac{1}{5} and the y-intercept b=3b = 3.

Would you like more details or have any questions about the solution? Here are some related questions for further practice:

  1. What is the slope of the line in the equation Y=15x+3Y = \frac{1}{5}x + 3?
  2. How do you graph the equation Y=15x+3Y = \frac{1}{5}x + 3?
  3. If x=10x = 10, what is the value of YY in the equation?
  4. How do you convert the equation to standard form Ax+By=CAx + By = C?
  5. What is the y-intercept of the line represented by this equation?

Tip: When solving equations involving fractions, distributing first often simplifies the equation.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Slope-Intercept Form
Distributive Property

Formulas

Slope-Intercept Form: Y = mx + b
Distributive Property: a(b + c) = ab + ac

Theorems

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Suitable Grade Level

Grades 6-8