Write an equation in slope intercept form:  y - 5 = -2(x + 1)

Remember, no spaces in your answer and all your variables are lower case.

To write the equation \(y - 5 = -2(x + 1)\) in slope-intercept form (which is \(y = mx + b\)), follow these steps:

1. Distribute the \(-2\) on the right side:
   \[
   y - 5 = -2x - 2
   \]

2. Add 5 to both sides to isolate \(y\):
   \[
   y = -2x + 3
   \]

Thus, the equation in slope-intercept form is:

\[
y=-2x+3
\]

Would you like more details on how this was done or have any questions?

Here are 5 related questions:
1. How do you find the slope from the equation \(y = mx + b\)?
2. How do you graph the equation \(y = -2x + 3\)?
3. What is the slope and y-intercept of \(y = -2x + 3\)?
4. How can you convert a point-slope form equation to slope-intercept form?
5. What is the effect of changing the slope \(m\) on the graph?

**Tip:** The y-intercept (\(b\)) is where the line crosses the y-axis, making it easy to start graphing!

Write an equation in slope intercept form: y - 5 = -2(x + 1)

Learn how to convert the linear equation y - 5 = -2(x + 1) into slope-intercept form. This step-by-step solution explains the use of the distributive property and how to isolate y to get the equation into the form y = mx + b. Ideal for students in Grades 7-9.

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