Math Problem Statement

y = 2y+1 all over 5

Solution

To solve the equation:

y=2y+15y = \frac{2y + 1}{5}

Step-by-step Solution:

  1. Eliminate the denominator: Multiply both sides of the equation by 5 to get rid of the denominator:

5y=2y+15y = 2y + 1

  1. Isolate the variable: Subtract 2y2y from both sides:

5y2y=15y - 2y = 1

3y=13y = 1

  1. Solve for yy: Divide both sides by 3:

y=13y = \frac{1}{3}

So, the solution is:

y=13y = \frac{1}{3}

Do you want further details or have any questions?

Here are five related questions to expand your understanding:

  1. How would the solution change if the equation was y=2y15y = \frac{2y - 1}{5}?
  2. Can you solve for yy if y=3y+27y = \frac{3y + 2}{7}?
  3. What if the equation involved a different variable, such as x=2x+15x = \frac{2x + 1}{5}?
  4. How would you solve 2y=4y+252y = \frac{4y + 2}{5}?
  5. Can you solve y=5y+310y = \frac{5y + 3}{10}?

Tip: When dealing with fractions, it's helpful to eliminate the denominator early by multiplying both sides of the equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

y = (2y + 1) / 5
Isolate variable by eliminating denominators

Theorems

Basic algebraic manipulation

Suitable Grade Level

Grades 6-8