We are given the equation:

\[
x + 3y + 200z = 89
\]
and that \( x = 1 \). To find \( y \), we can substitute \( x = 1 \) into the equation:

\[
1 + 3y + 200z = 89
\]

Simplifying:

\[
3y + 200z = 88
\]

At this point, we need more information about \( z \) to solve for \( y \). Do you have a value for \( z \), or is it expected to solve in terms of \( z \)?

Let me know if you want further clarification.

### 5 Relative Questions:
1. What would happen if \( z \) were a specific value, like 0?
2. Can we solve for \( y \) in terms of \( z \)?
3. How would changing \( z \) affect the value of \( y \)?
4. What is the general solution when there are multiple unknowns in an equation?
5. What if additional conditions were provided for \( y \) and \( z \)?

**Tip:** When you have multiple unknowns in an equation, you typically need as many equations as unknowns to solve for specific values.

Discover how to solve the linear equation X+3y+200z=89 when x=1. This solution uses algebraic methods like substitution to simplify the equation, demonstrating key concepts in solving linear equations with multiple variables. Ideal for students in Grades 8-10.

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