Math Problem Statement

If lim_{n \to \infty} \sum_{j=1}^n \frac{6}{n} f(6 + \frac{3j}{n}) = 6 for some function f(x), then \int_6^9 f(x) dx = __?

Solution

This problem involves recognizing the expression as a Riemann sum and solving for the integral.

The given limit is:

limnj=1n6nf(6+3jn)=6\lim_{n \to \infty} \sum_{j=1}^n \frac{6}{n} f\left(6 + \frac{3j}{n}\right) = 6

Step-by-Step Explanation:

  1. Recognize the Riemann Sum:
    The expression corresponds to the Riemann sum definition of a definite integral: abf(x)dx=limnj=1nΔxf(xj),\int_a^b f(x) \, dx = \lim_{n \to \infty} \sum_{j=1}^n \Delta x \cdot f(x_j), where:

    • Δx=ban\Delta x = \frac{b-a}{n} (width of each subinterval),
    • xj=a+jΔxx_j = a + j \Delta x (sample point in the interval).

    Here:

    • Δx=6n\Delta x = \frac{6}{n},
    • xj=6+3jnx_j = 6 + \frac{3j}{n}.

    From Δx=6n\Delta x = \frac{6}{n}, the interval length is 66. This tells us ba=6b - a = 6.

    From xj=6+3jnx_j = 6 + \frac{3j}{n}, the interval starts at x=6x = 6. Thus: a=6,b=6+3=9.a = 6, \quad b = 6 + 3 = 9.

    Therefore, the Riemann sum is approximating the integral: 69f(x)dx.\int_6^9 f(x) \, dx.

  2. Equating to the Given Value: The problem states that the Riemann sum converges to 66. Thus: 69f(x)dx=6.\int_6^9 f(x) \, dx = 6.

Final Answer:

6\boxed{6}

Would you like a detailed explanation of any step? Let me know!

Related Questions:

  1. What is a Riemann sum, and how does it relate to definite integrals?
  2. How do you determine the bounds aa and bb of an integral from a Riemann sum?
  3. How do you solve for Δx\Delta x and xjx_j in a Riemann sum?
  4. Can you explain how to evaluate definite integrals with substitution methods?
  5. What are common mistakes when interpreting limits of Riemann sums?

Tip:

Always match the form of a Riemann sum to its integral by carefully identifying Δx\Delta x, the sample points, and the interval bounds.

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Math Problem Analysis

Mathematical Concepts

Calculus
Riemann Sums
Definite Integrals

Formulas

Definite Integral: \int_a^b f(x) \, dx = \lim_{n \to \infty} \sum_{j=1}^n \Delta x \cdot f(x_j)
Riemann Sum: \Delta x = \frac{b-a}{n}, x_j = a + j \Delta x

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Grades 11-12 or introductory college-level calculus