Your expression seems to involve logarithms, but it is a bit unclear. It looks like you're working with:

- Base-2 logarithms, possibly written as \( \log_2 \)
- There seems to be some reference to "64" and fractions such as \( \frac{1}{6} \), but the format is ambiguous.  
Let me interpret it as follows, based on what I think you're aiming for:

### Interpretation:  
\[
\log_2 + \log_2 64 - \log_2 \left(\frac{1}{6}\right)
\]

If this is correct, let’s solve it step by step.

---

### Step 1: Simplify \( \log_2 64 \)  
Since \( 64 = 2^6 \), we know:
\[
\log_2 64 = 6
\]

---

### Step 2: Simplify \( \log_2 \left(\frac{1}{6}\right) \)  
Using logarithm properties:
\[
\log_2 \left(\frac{1}{6}\right) = \log_2 1 - \log_2 6 = 0 - \log_2 6 = -\log_2 6
\]

We leave \( \log_2 6 \) as is, or approximate it:
\[
\log_2 6 \approx 2.585
\]
Thus:
\[
-\log_2 6 \approx -2.585
\]

---

### Step 3: Combine Terms  
Now the expression is:
\[
\log_2 + 6 - (-2.585)
\]

Since there is no value provided for the first \( \log_2 \), it may be a typo. Assuming it's intended to be zero:
\[
0 + 6 + 2.585 = 8.585
\]

---

### Final Answer:
\[
\boxed{8.585}
\]

If my interpretation differs from your intent, please clarify! I'll be happy to adjust the solution.

---

Would you like further details or have any questions?  
Here are five related questions that expand on this topic:

1. How do we solve logarithms with different bases, like \( \log_3(27) \)?  
2. What are the key logarithmic properties for solving complex problems?  
3. How do logarithms relate to exponential functions?  
4. Can you express \( \log_2(6) \) exactly or only approximately?  
5. How do negative arguments inside logarithms behave?  

**Tip:** Remember that \( \log_b(xy) = \log_b(x) + \log_b(y) \) helps with simplifying products inside logarithms.

Solve the logarithmic expression log_2 + log_2 64 - log_2 (1/6) with step-by-step guidance. Learn to apply logarithmic properties, including log of powers and log of fractions. Suitable for high school students in Grades 9-12.

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