To solve $\log_2 64$, we need to determine the power to which 2 must be raised to get 64.

$\log_2 64 = x \implies 2^x = 64$

Now, express 64 as a power of 2:

$64 = 2^6$

So,

$2^x = 2^6$

Therefore, $x = 6$.

Thus, $\log_2 64 = 6$.

Would you like more details or have any questions? Here are 5 related questions you might find interesting:

1. What is $\log_2 32$?
2. How would you solve $\log_3 81$?
3. What is the value of $\log_{10} 1000$?
4. How do you evaluate $\log_2 1$?
5. What is $\log_4 64$?

Tip: Remember, logarithms can be thought of as the inverse operation of exponentiation.