To solve \(\log_2 64\), we need to determine the power to which 2 must be raised to get 64.

\[
\log_2 64 = x \implies 2^x = 64
\]

Now, express 64 as a power of 2:

\[
64 = 2^6
\]

So,

\[
2^x = 2^6
\]

Therefore, \(x = 6\).

Thus, \(\log_2 64 = 6\).

Would you like more details or have any questions? Here are 5 related questions you might find interesting:

1. What is \(\log_2 32\)?
2. How would you solve \(\log_3 81\)?
3. What is the value of \(\log_{10} 1000\)?
4. How do you evaluate \(\log_2 1\)?
5. What is \(\log_4 64\)?

**Tip:** Remember, logarithms can be thought of as the inverse operation of exponentiation.

Discover how to solve the logarithm problem log2(64) step-by-step. This solution covers key mathematical concepts, including logarithms and exponents, with the formula log_b(x) = y and exponentiation properties. Suitable for students in Grades 8-10.

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