Let's break down the expression step-by-step. The given expression is:

$\frac{40}{-5} - \frac{-16}{8} + \frac{39}{3} - 6^0$

Now let's solve it in parts:

1. First term:
   $\frac{40}{-5} = -8$

2. Second term:
   $\frac{-16}{8} = -2$ Since there is a negative sign before this fraction, this becomes: $-(-2) = 2$

3. Third term:
   $\frac{39}{3} = 13$

4. Fourth term:
   $6^0 = 1$ Since any number raised to the power of 0 is 1.

Now, let's combine all these values into the original expression:

$-8 + 2 + 13 - 1$

Step-by-step calculation:

$-8 + 2 = -6$

$-6 + 13 = 7$

$7 - 1 = 6$

So, the final result of the expression is 6.

Would you like more details or have any questions?

Related Questions:

1. What happens if the base in an exponent expression like $6^0$ is negative?
2. How do you simplify expressions with multiple fractions?
3. What is the rule for multiplying and dividing negative numbers?
4. How do exponents work with fractions?
5. How do you handle more complex expressions involving multiple operations?

Tip: When simplifying expressions, remember to follow the order of operations (PEMDAS/BODMAS) to avoid mistakes.