Let's solve Question 5 and Question 6 step by step.

Question 5:

$-5 + (-4) - 3 \cdot 11 + (-2)^3$

1. Simplify each part step by step:

   • $-5 + (-4) = -9$
   • $3 \cdot 11 = 33$
   • $(-2)^3 = -8$ (because $-2 \cdot -2 \cdot -2 = -8$)

2. Substitute back into the equation: $-9 - 33 + (-8)$

3. Combine:

   • $-9 - 33 = -42$
   • $-42 + (-8) = -50$

Final Answer for Question 5: $\boxed{-50}$

Question 6:

$\frac{6 - (-4)}{-2} + \frac{-2 + 14}{-4}$

1. Simplify the numerators and denominators step by step:

   • $6 - (-4) = 6 + 4 = 10$, so $\frac{10}{-2} = -5$
   • $-2 + 14 = 12$, so $\frac{12}{-4} = -3$

2. Combine the results: $-5 + (-3) = -5 - 3 = -8$

Final Answer for Question 6: $\boxed{-8}$

Do you need further explanation on any step? Let me know!

Related Questions:

1. Simplify $(-3)^2 + (-4)^2 - 5 \cdot 2$.
2. Solve $\frac{-12 + 8}{4} + \frac{16 - 4}{2}$.
3. Evaluate $3 \cdot (-5)^2 - (-2)^3 + 7$.
4. Calculate $\frac{5 - (-3)}{2} - \frac{8 + 4}{-4}$.
5. Simplify $(-6 + 9) \cdot (-2) + (-3)^2$.

Tip:

Always follow the order of operations: Parentheses, Exponents, Multiplication/Division (left to right), Addition/Subtraction (left to right) — also known as PEMDAS.