To simplify the square root of 80, we can follow these steps:

1. Factor 80 into its prime factors: $80 = 2 \times 40 = 2 \times 2 \times 20 = 2 \times 2 \times 2 \times 10 = 2 \times 2 \times 2 \times 2 \times 5 = 2^4 \times 5$

2. Apply the square root to the factors: $\sqrt{80} = \sqrt{2^4 \times 5}$

3. Simplify by taking the square root of perfect squares: $\sqrt{2^4 \times 5} = \sqrt{2^4} \times \sqrt{5} = 2^2 \times \sqrt{5} = 4\sqrt{5}$

So, the simplified form of $\sqrt{80}$ is $4\sqrt{5}$.

Would you like any further details or have any questions?

Here are some related questions for further practice:

1. How would you simplify $\sqrt{45}$?
2. What is $\sqrt{180}$ in its simplest form?
3. If $\sqrt{x} = 7 \sqrt{5}$, what is the value of $x$?
4. Simplify $\sqrt{50}$.
5. How would you write $\sqrt{128}$ as a product of a whole number and a square root?
6. What is the simplified form of $\sqrt{98}$?
7. Can $\sqrt{a}$ be simplified further if $a = 200$?
8. What is the square root of 72 in simplest radical form?

Tip: When simplifying square roots, always factor the number into its prime factors and look for perfect squares!