To simplify $\sqrt{80}$ into the form $a\sqrt{b}$, follow these steps:

1. Find the prime factorization of 80: $80 = 2^4 \times 5$

2. Rewrite $\sqrt{80}$ as $\sqrt{2^4 \times 5}$.

3. Split the square root: $\sqrt{80} = \sqrt{2^4} \times \sqrt{5}$

4. Simplify $\sqrt{2^4}$: $\sqrt{2^4} = 2^2 = 4$

5. Now, you have: $\sqrt{80} = 4\sqrt{5}$

Thus, $\sqrt{80}$ simplified is $4\sqrt{5}$.

Would you like further details on this solution or have any questions?

Here are 5 related questions you might want to explore:

1. How would you simplify $\sqrt{200}$?
2. Can you express $\sqrt{18}$ in the form $a\sqrt{b}$?
3. What is the simplified form of $\sqrt{50}$?
4. How would you solve $\sqrt{72}$ to $a\sqrt{b}$?
5. How do you simplify the expression $3\sqrt{45}$?

Tip: When simplifying square roots, always look for perfect squares within the radicand to simplify the expression efficiently.