Let's break down the expression step by step.

The expression given is:

$(\text{i} \sqrt{7})^2 \times 2\text{i}$

Step 1: Square the first term.

$(\text{i} \sqrt{7})^2 = \text{i}^2 \times (\sqrt{7})^2$

$\text{i}^2 = -1$ and $(\sqrt{7})^2 = 7$, so: $(\text{i} \sqrt{7})^2 = -1 \times 7 = -7$

Step 2: Multiply the result by $2\text{i}$.

Now multiply $-7$ by $2\text{i}$: $-7 \times 2\text{i} = -14\text{i}$

So the final answer is:

$-14\text{i}$

Would you like to go into more detail or have any questions? Here are some related questions to explore further:

1. What is the general formula for the square of a complex number?
2. How does multiplying complex numbers differ from multiplying real numbers?
3. Can you explain why $\text{i}^2 = -1$?
4. What happens if you multiply two purely imaginary numbers?
5. How do you add or subtract complex numbers?

Tip: When dealing with imaginary numbers, remember that $\text{i}^2 = -1$ is a key property that simplifies many expressions.