Math Problem Statement
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Solution
The problem describes a signal with two baseband components: one has a rectangular spectrum, and the other has a triangular spectrum, modulated onto two different carriers. The spectrum of the received signal shows these two components centered at different frequencies, ensuring that their spectra do not overlap.
From the image:
- The rectangular spectrum is centered at 110 kHz and spans from 85 kHz to 135 kHz (a bandwidth of 50 kHz).
- The triangular spectrum is centered at -110 kHz and spans from -135 kHz to -85 kHz.
The signal is demodulated by mixing with a cosine at 110 kHz. This shifts the rectangular baseband signal centered at 110 kHz down to 0 kHz (baseband). The triangular spectrum, originally centered at -110 kHz, is shifted by the same 110 kHz, meaning it will now appear centered at -220 kHz.
To isolate the rectangular spectrum (now at baseband), an ideal low-pass filter must pass the signal from 0 kHz to 25 kHz (the positive half of the baseband signal), since the rectangular spectrum originally spanned from 85 kHz to 135 kHz.
Therefore, the correct answer is:
A. 25 kHz
Would you like further details or have any other questions?
Here are 5 related questions to expand your understanding:
- What is the significance of the triangular and rectangular spectrum shapes in real-world signals?
- How does demodulating a signal with a cosine shift the spectrum?
- What would happen if the triangular signal had a frequency closer to 110 kHz?
- Why is it important that the signals occupy non-overlapping regions of the spectrum?
- How does a low-pass filter affect signals after demodulation?
Tip: When using a cosine for demodulation, the frequency of the cosine defines the shift, and the result needs careful filtering to isolate the desired component.
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Math Problem Analysis
Mathematical Concepts
Signal Processing
Fourier Transform
Modulation
Filtering
Formulas
Fourier transform
Low-pass filter transfer function
Theorems
Shifting property of Fourier transform
Nyquist-Shannon sampling theorem
Suitable Grade Level
University level