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### Question (a): Find \( Y(t) \) as a function of \( X(t) \)
The relationship between \( X(f) \) and \( Y(f) \) suggests a **frequency shift** because the frequency spectrum of \( Y(f) \) has shifted components compared to \( X(f) \).

- **Given Observations**:
  1. \( X(f) \) is a triangular pulse spanning from \(-3400\) Hz to \( 3400 \) Hz, with a peak magnitude of 10 at 0 Hz.
  2. \( Y(f) \) has its components shifted to center around \(\pm 10 \, \text{kHz}\) and reduced in amplitude. The peak magnitude is 12, and the triangle width is smaller.

- **Frequency Shift**:
  \( Y(f) \) is derived from \( X(f) \) by shifting \( X(f) \) to \( \pm 10 \, \text{kHz} \) and scaling. This implies:
  \[
  Y(f) = 12 \cdot X(f \pm 10,000)
  \]

- **Time Domain Representation**:
  A shift in the frequency domain corresponds to a multiplication in the time domain by a complex exponential:
  \[
  Y(t) = 12 \cdot X(t) \cdot \cos(2\pi \cdot 10,000t)
  \]
  This result is the modulated version of \( X(t) \) by a carrier frequency at \( 10 \, \text{kHz} \).

### Question (b): Sketch the frequency spectrum of \( Z(t) \), where
\[
Z(t) = Y(t) \cos(2\pi \cdot 30,000t)
\]
#### Step 1: Understand \( Z(t) \)'s Modulation
Modulating \( Y(t) \) by \( \cos(2\pi \cdot 30,000t) \) results in another frequency shift. In the frequency domain, the modulation by \( \cos(2\pi \cdot 30,000t) \) corresponds to splitting \( Y(f) \) into two shifted components:
- \( Y(f) \) is shifted by \( +30,000 \, \text{Hz} \) and \( -30,000 \, \text{Hz} \).

#### Step 2: Analyze the Spectrum
The original \( Y(f) \) consists of two triangular pulses centered at \(\pm 10 \, \text{kHz}\). Modulating \( Y(f) \) by \( \cos(2\pi \cdot 30,000t) \) produces:
1. One set of triangular pulses centered at \( \pm 40 \, \text{kHz} \) (from \( +10,000 + 30,000 \)).
2. Another set of triangular pulses centered at \( \pm 20 \, \text{kHz} \) (from \( -10,000 + 30,000 \)).

#### Step 3: Final Spectrum
The new frequency spectrum \( Z(f) \) will have:
- Two triangular components centered at \( \pm 40 \, \text{kHz} \), each scaled by the factor from \( Y(f) \).
- Two triangular components centered at \( \pm 20 \, \text{kHz} \).

### Final Answers:
(a) \( Y(t) = 12 \cdot X(t) \cdot \cos(2\pi \cdot 10,000t) \)

(b) The frequency spectrum \( Z(f) \) consists of:
- Two triangular pulses centered at \( \pm 40 \, \text{kHz} \).
- Two triangular pulses centered at \( \pm 20 \, \text{kHz} \).

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Let me know if you'd like detailed sketches or have further questions! Here's how we can expand:

1. Why does a frequency shift in \( X(f) \) cause modulation in \( X(t) \)?
2. How can amplitude scaling in \( X(f) \) affect \( X(t) \)?
3. What are the advantages of frequency modulation in communication systems?
4. What is the relationship between bandwidth and the width of the triangular pulses in this problem?
5. How do you mathematically verify the result for \( Z(t) \)?

**Tip**: Always ensure the units are consistent (Hz vs kHz) while analyzing spectra.

For the given frequency spectrum of X(f) and Y(f), (a) Find Y(t) as a function of X(t). (b) If Z(t) = Y(t)Cos(2π * 30000t), sketch the frequency spectrum of Z(t).

Explore how to derive Y(t) as a modulated version of X(t) using Fourier Transform principles and analyze the frequency spectrum of Z(t) under cosine modulation at 30 kHz. This problem covers key concepts of Fourier Transform, frequency shifting, and modulation.

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