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The question asks: "How many ways are there to select five math help websites from a list that contains twelve different websites?"

This is a **combinatorics** problem, specifically about combinations, because the order of selection does not matter.

The formula for combinations is given by:

\[
C(n, k) = \frac{n!}{k!(n-k)!}
\]

where \( n \) is the total number of items (12 websites), and \( k \) is the number of items to choose (5 websites).

So, in this case, we need to calculate \( C(12, 5) \):

\[
C(12, 5) = \frac{12!}{5!(12-5)!} = \frac{12!}{5!7!}
\]

I'll compute this.The number of ways to select five math help websites from a list of twelve different websites is **792**.

Do you want further details on this, or have any other questions?

Here are five related questions to explore:
1. What if the list contained 15 websites instead of 12?
2. How would the result change if the order of selection mattered (permutations)?
3. How can combinations be used in probability problems?
4. How many ways can you select 5 websites from 12 if repetition of websites were allowed?
5. What is the difference between combinations and permutations in general?

**Tip**: When solving selection problems, remember that combinations deal with groups where the order doesn't matter, while permutations deal with groups where the order is important.

How many ways are there to select five math help websites from a list that contains twelve different websites?

Discover how to calculate the number of ways to select five websites from a list of twelve different websites using combinations. This combinatorics problem is suitable for Grades 9-12 and covers key concepts like combination formulas.

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