SEAWATER PRESSURE - IN SEAWATER, THE PRESSURE p IS RELATED TO THE DEPTH
d ACCORDING TO 33p - 18d = 495 WHERE d IS IN FEET AND p IS IN POUNDS PER
SQUARE INCH. THE TITANIC WAS DISCOVERED AT A DEPTH OF 12,460 FEET. FIND THE PRESSURE AT THIS DEPTH.

We are given the equation relating the pressure \( p \) and the depth \( d \) in seawater:

\[
33p - 18d = 495
\]

We need to find the pressure at a depth of \( d = 12,460 \) feet.

### Step 1: Substitute \( d = 12,460 \) into the equation.

\[
33p - 18(12,460) = 495
\]

### Step 2: Calculate \( 18 \times 12,460 \).

\[
18 \times 12,460 = 224,280
\]

So, the equation becomes:

\[
33p - 224,280 = 495
\]

### Step 3: Add \( 224,280 \) to both sides to isolate the term with \( p \).

\[
33p = 495 + 224,280
\]

\[
33p = 224,775
\]

### Step 4: Solve for \( p \) by dividing both sides by 33.

\[
p = \frac{224,775}{33}
\]

\[
p = 6,810.61 \, \text{psi}
\]

### Final Answer:
The pressure at a depth of 12,460 feet is approximately \( 6,810.61 \, \text{psi} \).

Do you want further details or have any questions?

Here are 5 related questions for practice:
1. If the depth is doubled, what will be the pressure?
2. At what depth would the pressure reach 10,000 psi?
3. How does changing the coefficient of \( d \) affect the pressure-depth relationship?
4. What would be the pressure at 5,000 feet using the same equation?
5. How is the relationship between depth and pressure affected by different liquids?

**Tip:** When working with equations, isolating variables step by step helps ensure accuracy and prevents mistakes.

SEAWATER PRESSURE - IN SEAWATER, THE PRESSURE p IS RELATED TO THE DEPTH d ACCORDING TO 33p - 18d = 495 WHERE d IS IN FEET AND p IS IN POUNDS PER SQUARE INCH. THE TITANIC WAS DISCOVERED AT A DEPTH OF 12,460 FEET. FIND THE PRESSURE AT THIS DEPTH.

Discover how to find the seawater pressure at a depth of 12,460 feet using the linear equation 33p - 18d = 495. This problem covers algebraic concepts and is ideal for high school students in Grades 9-11.

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