The image shows a question about water pressure at various depths below the ocean's surface. The formula given is:

$P = 16 + \frac{6}{13}d$

where:

• $P$ is the pressure of seawater in pounds per square foot,
• $d$ is the depth below the surface in feet.

The task is to compute the water pressure at different depths using this formula.

First part of the question:

You are given that the pressure is 100 pounds per square foot at a depth of 182 feet, and the first box has already been answered correctly.

Now, you are asked to find the pressure at a depth of 95 feet.

Solution:

We will plug $d = 95$ into the formula to compute the pressure $P$:

$P = 16 + \frac{6}{13} \times 95$

Let me calculate that for you.The pressure of sea water at a depth of 95 feet is approximately $59.85$ pounds per square foot.

Would you like any further details or clarifications?

Here are some related questions you might find helpful:

1. What is the physical significance of the constant 16 in the equation?
2. How does the pressure change with increasing depth according to the formula?
3. What would the depth be for a given pressure, say 120 pounds per square foot?
4. Can this formula be used for extreme depths? Why or why not?
5. How does water density affect the pressure increase at various depths?

Tip: For linear equations like this one, the slope tells you how quickly the pressure changes per unit of depth.