We are tasked with solving the expression:

\[
\frac{(-1.6 \times 10^{-19}) \times 245}{9.109 \times 10^{-31}}
\]

### Step-by-Step Solution:

1. Multiply \((-1.6 \times 10^{-19})\) by \(245\):
   \[
   (-1.6 \times 10^{-19}) \times 245 = -392 \times 10^{-19}
   \]

2. Now divide by \(9.109 \times 10^{-31}\):
   \[
   \frac{-392 \times 10^{-19}}{9.109 \times 10^{-31}} = -392 \times 10^{12} \div 9.109
   \]

3. Perform the division:
   \[
   \frac{-392}{9.109} \approx -43.03
   \]

4. Add the powers of 10:
   \[
   -43.03 \times 10^{12}
   \]

5. Final answer in scientific notation:
   \[
   \approx -4.303 \times 10^{13}
   \]

### The solution is:
\[
-4.303 \times 10^{13}
\]

Would you like further details or have any questions?

---

Here are five related questions to expand on the concept:

1. How would the result change if the exponent in the denominator were different?
2. What is the physical significance of the constants used in the expression?
3. How can you express the result using different units or notations?
4. How do you handle operations with very small or very large numbers more efficiently?
5. How does scientific notation help in simplifying such calculations?

**Tip:** When multiplying and dividing with powers of 10, you can simplify operations by focusing on the powers of 10 separately from the numbers.

This page explains how to solve a scientific notation division problem: ((-1.6×10^-19)(245)) / (9.109×10^-31). Follow a detailed step-by-step breakdown, including exponent rules and algebraic concepts. Ideal for Grades 10-12.

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