Math Problem Statement

Sasa had some 20-cent and 50-cent coins. Let x be the total number of coins. Then, 7/8 x were 20-cent coins, and the rest, 1 - 7/8 = 1/8 x, were 50-cent coins. After Sasa spent $72.50 worth of 50-cent coins, which is equivalent to 72.50 / 0.50 = 145 50-cent coins, and 5/7 of the 20-cent coins, she had 2/7 x coins left. Find the total amount of money Sasa left.

Solution

Let xx be the total number of coins Sasa had initially.

Step 1: Determine the number of each type of coin.

  • The number of 20-cent coins is 78x\frac{7}{8}x.
  • The number of 50-cent coins is 18x\frac{1}{8}x.

Step 2: Analyze the situation after Sasa spent some of her coins.

  • Sasa spent 145 50-cent coins. Therefore, the total number of 50-cent coins she initially had must have been at least 145. This implies: 18x145.\frac{1}{8}x \geq 145. Multiplying both sides by 8: x1160.x \geq 1160.

  • Sasa also spent 57\frac{5}{7} of her 20-cent coins. The number of 20-cent coins remaining is 27\frac{2}{7} of 78x\frac{7}{8}x, which is: 27×78x=28x=14x.\frac{2}{7} \times \frac{7}{8}x = \frac{2}{8}x = \frac{1}{4}x.

Step 3: Total coins left.

Sasa was left with 27x\frac{2}{7}x coins in total, so the sum of the remaining 20-cent and 50-cent coins should equal 27x\frac{2}{7}x. The number of remaining 20-cent coins is 14x\frac{1}{4}x, so the number of remaining 50-cent coins is: 27x14x.\frac{2}{7}x - \frac{1}{4}x. To simplify this, find a common denominator: 27x=828xand14x=728x,\frac{2}{7}x = \frac{8}{28}x \quad \text{and} \quad \frac{1}{4}x = \frac{7}{28}x, so: 828x728x=128x.\frac{8}{28}x - \frac{7}{28}x = \frac{1}{28}x. Thus, the number of remaining 50-cent coins is 128x\frac{1}{28}x.

Step 4: Calculate the total value of the remaining coins.

The total value of the remaining 20-cent coins is: 14x×0.20=0.05x.\frac{1}{4}x \times 0.20 = 0.05x. The total value of the remaining 50-cent coins is: 128x×0.50=0.5028x=0.017857x.\frac{1}{28}x \times 0.50 = \frac{0.50}{28}x = 0.017857x.

Thus, the total value of the remaining coins is: 0.05x+0.017857x=0.067857x.0.05x + 0.017857x = 0.067857x.

Step 5: Solve for xx.

Since Sasa spent 145 50-cent coins, the total number of 50-cent coins initially was 18x=145\frac{1}{8}x = 145, so: x=145×8=1160.x = 145 \times 8 = 1160.

Step 6: Calculate the total amount of money Sasa has left.

Now substitute x=1160x = 1160 into the expression for the total value of the remaining coins: 0.067857×1160=78.71.0.067857 \times 1160 = 78.71.

Thus, the total amount of money Sasa has left is $78.71.


Would you like more details, or do you have any further questions? Here are 5 related questions you can explore:

  1. How would the answer change if Sasa spent 67\frac{6}{7} of her 20-cent coins?
  2. What if Sasa had spent 160 50-cent coins instead of 145?
  3. Can you determine how much money Sasa initially had before spending any coins?
  4. How would the problem change if Sasa had 9/10 of her coins as 20-cent coins instead of 7/8?
  5. How can this be solved using algebraic expressions for both types of coins?

Tip: Always break down a problem step by step, especially when dealing with fractions and large numbers.

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Math Problem Analysis

Mathematical Concepts

Algebra
Proportions
Coin Value Calculations

Formulas

Total coins remaining: 2/7x
Remaining 50-cent coins: 1/28x
Value of remaining 20-cent coins: (1/4)x * 0.20
Value of remaining 50-cent coins: (1/28)x * 0.50

Theorems

Basic algebraic manipulation
Proportion calculation

Suitable Grade Level

Grades 8-10