To find the resultant vector of two forces acting on a car, we need to calculate both the magnitude and direction of the resultant force vector using vector addition.

Since you mentioned a figure but did not upload it, I'll assume the following based on typical scenarios:

• The force F₁ (400 N) acts in a direction (perhaps angled from the horizontal).
• The force F₂ (359 N) acts in a different direction, possibly at another angle.

We'll proceed by using vector components:

Steps:

1. Resolve the forces into components along the horizontal (x-axis) and vertical (y-axis).

   If the angles between the forces and the horizontal axis were provided, we would use the trigonometric functions:

   • $F_{1x} = F_1 \cdot \cos(\theta_1)$
   • $F_{1y} = F_1 \cdot \sin(\theta_1)$
   • $F_{2x} = F_2 \cdot \cos(\theta_2)$
   • $F_{2y} = F_2 \cdot \sin(\theta_2)$

2. Find the resultant components by summing the horizontal and vertical components:

   • $R_x = F_{1x} + F_{2x}$
   • $R_y = F_{1y} + F_{2y}$

3. Magnitude of the resultant force is given by: $R = \sqrt{R_x^2 + R_y^2}$

4. Direction (angle) of the resultant force can be found using: $\theta = \tan^{-1}\left(\frac{R_y}{R_x}\right)$

If you upload the image or provide the angles, I can proceed with more precise calculations.

Do you have the figure or angles for the forces? Let me know, and I can guide you further.

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Related Questions:

1. How do we calculate the resultant of three or more forces?
2. What happens if the forces are at right angles?
3. How can you calculate the resultant if the angles are not given directly?
4. What are the conditions for equilibrium in force systems?
5. How does the direction of the resultant vector change with different force magnitudes?

Tip: Always resolve vectors into components when dealing with forces at angles to simplify calculations.