Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let 
F1 = 400 N
 and 
F2 = 359 N.
 Assume up and to the right are in the positive directions.) What is the resultant vector of these two forces? magnitude and direction?

To find the resultant vector of two forces acting on a car, we need to calculate both the magnitude and direction of the resultant force vector using vector addition. 

Since you mentioned a figure but did not upload it, I'll assume the following based on typical scenarios:

- The force **F₁** (400 N) acts in a direction (perhaps angled from the horizontal).
- The force **F₂** (359 N) acts in a different direction, possibly at another angle.

We'll proceed by using vector components:

### Steps:
1. **Resolve the forces into components** along the horizontal (**x-axis**) and vertical (**y-axis**).
   
   If the angles between the forces and the horizontal axis were provided, we would use the trigonometric functions:
   - \( F_{1x} = F_1 \cdot \cos(\theta_1) \)
   - \( F_{1y} = F_1 \cdot \sin(\theta_1) \)
   - \( F_{2x} = F_2 \cdot \cos(\theta_2) \)
   - \( F_{2y} = F_2 \cdot \sin(\theta_2) \)

2. **Find the resultant components** by summing the horizontal and vertical components:
   - \( R_x = F_{1x} + F_{2x} \)
   - \( R_y = F_{1y} + F_{2y} \)

3. **Magnitude of the resultant force** is given by:
   \[
   R = \sqrt{R_x^2 + R_y^2}
   \]

4. **Direction (angle)** of the resultant force can be found using:
   \[
   \theta = \tan^{-1}\left(\frac{R_y}{R_x}\right)
   \]

If you upload the image or provide the angles, I can proceed with more precise calculations. 

Do you have the figure or angles for the forces? Let me know, and I can guide you further.

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### Related Questions:
1. How do we calculate the resultant of three or more forces?
2. What happens if the forces are at right angles?
3. How can you calculate the resultant if the angles are not given directly?
4. What are the conditions for equilibrium in force systems?
5. How does the direction of the resultant vector change with different force magnitudes?

**Tip:** Always resolve vectors into components when dealing with forces at angles to simplify calculations.

Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let F1 = 400 N and F2 = 359 N. Assume up and to the right are in the positive directions.) What is the resultant vector of these two forces? Magnitude and direction?

Learn how to calculate the resultant vector for two forces, 400 N and 359 N, applied to a car. This solution covers vector addition, the Pythagorean theorem, and trigonometry for determining both magnitude and direction. Suitable for students in Grades 10-12.

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