Math Problem Statement

What is the direction of the resultant vector when adding (a+b+c+d), when a is 25 N at 0 degrees, b is 35 N at 180 degrees, c is 50 N at 270 degrees, and d is 30 N at 90 degrees?

Solution

To find the direction of the resultant vector when adding vectors a+b+c+da + b + c + d, we need to break each vector into its horizontal (x) and vertical (y) components and then sum them up.

Step 1: Break each vector into components

  1. Vector aa (25 N at 0 degrees):

    • Horizontal component (x): ax=25cos(0)=25Na_x = 25 \cos(0^\circ) = 25 \, \text{N}
    • Vertical component (y): ay=25sin(0)=0Na_y = 25 \sin(0^\circ) = 0 \, \text{N}
  2. Vector bb (35 N at 180 degrees):

    • Horizontal component (x): bx=35cos(180)=35Nb_x = 35 \cos(180^\circ) = -35 \, \text{N}
    • Vertical component (y): by=35sin(180)=0Nb_y = 35 \sin(180^\circ) = 0 \, \text{N}
  3. Vector cc (50 N at 270 degrees):

    • Horizontal component (x): cx=50cos(270)=0Nc_x = 50 \cos(270^\circ) = 0 \, \text{N}
    • Vertical component (y): cy=50sin(270)=50Nc_y = 50 \sin(270^\circ) = -50 \, \text{N}
  4. Vector dd (30 N at 90 degrees):

    • Horizontal component (x): dx=30cos(90)=0Nd_x = 30 \cos(90^\circ) = 0 \, \text{N}
    • Vertical component (y): dy=30sin(90)=30Nd_y = 30 \sin(90^\circ) = 30 \, \text{N}

Step 2: Sum the components

  • Total horizontal component (x): Rx=ax+bx+cx+dx=25+(35)+0+0=10NR_x = a_x + b_x + c_x + d_x = 25 + (-35) + 0 + 0 = -10 \, \text{N}

  • Total vertical component (y): Ry=ay+by+cy+dy=0+0+(50)+30=20NR_y = a_y + b_y + c_y + d_y = 0 + 0 + (-50) + 30 = -20 \, \text{N}

Step 3: Calculate the magnitude of the resultant vector

R=Rx2+Ry2=(10)2+(20)2=100+400=50022.36NR = \sqrt{R_x^2 + R_y^2} = \sqrt{(-10)^2 + (-20)^2} = \sqrt{100 + 400} = \sqrt{500} \approx 22.36 \, \text{N}

Step 4: Calculate the direction (angle) of the resultant vector

The angle θ\theta is given by: θ=tan1(RyRx)=tan1(2010)=tan1(2)\theta = \tan^{-1}\left(\frac{R_y}{R_x}\right) = \tan^{-1}\left(\frac{-20}{-10}\right) = \tan^{-1}(2) θ63.43\theta \approx 63.43^\circ

Since both RxR_x and RyR_y are negative, the vector lies in the third quadrant, so the angle is measured from the negative x-axis: θ=180+63.43=243.43\theta = 180^\circ + 63.43^\circ = 243.43^\circ

Result:

The direction of the resultant vector is approximately 243.43 degrees.

Would you like more details or have any questions?


Here are 5 related questions to expand on this topic:

  1. How would the direction change if vector aa was at 90 degrees instead of 0 degrees?
  2. What is the resultant magnitude if one of the vectors had a different force value?
  3. How do we add vectors in three-dimensional space?
  4. How can we calculate the resultant vector if the vectors are not given at cardinal directions?
  5. What role does the angle of the vector play in determining the resultant?

Tip: Always break vectors into components (x and y) when solving vector addition problems.

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Math Problem Analysis

Mathematical Concepts

Vector Addition
Trigonometry
Vector Components

Formulas

Horizontal component: R_x = a_x + b_x + c_x + d_x
Vertical component: R_y = a_y + b_y + c_y + d_y
Magnitude: R = √(R_x^2 + R_y^2)
Direction: θ = tan^(-1)(R_y / R_x)

Theorems

Pythagorean Theorem
Trigonometric Functions

Suitable Grade Level

Grades 10-12