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The problem asks to construct the resultant of two forces (6 N and 8 N) and determine its magnitude.

To solve this, we need to consider the following:

1. **Given Forces**:
   - 6 N force acting horizontally to the right.
   - 8 N force acting at an angle downwards.

The angle between the two forces appears to be **90 degrees** (though it's not explicitly mentioned, the visual implies it). With that assumption, we can calculate the magnitude of the resultant force using the **Pythagorean theorem** since the forces are perpendicular:

\[
R = \sqrt{(6^2 + 8^2)}
\]

Let me calculate that for you.The magnitude of the resultant force is **10 N**.

Would you like further details or have any additional questions? Here are five related questions you might find interesting:

1. What happens if the angle between the two forces changes from 90 degrees?
2. How can we determine the direction of the resultant force?
3. What is the parallelogram method of vector addition?
4. How do you calculate the resultant force if the forces are not perpendicular?
5. How is the concept of force resolution applied in engineering problems?

**Tip**: When forces are perpendicular, the Pythagorean theorem provides a straightforward way to calculate the resultant force.

Konstruera resultanten till de två krafterna och bestäm dess storlek.

Learn how to calculate the resultant of two forces (6 N and 8 N) at a 90-degree angle using vector addition and the Pythagorean theorem. This solution is ideal for students in Grades 9-12, covering core concepts in physics and mathematics.

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