Math Problem Statement

MBA Nexus - CAT & OMETS 2024, [29-10-2024 09:13] Q6 A and B started running simultaneously from a point around a circular track of 900 m. The ratio of their speeds is 3 : 7. For how many times will A and B be at a distance of 10 m from each other, if they are running in opposite directions and stops only when they meet for the first time at the starting point again?

MBA Nexus - CAT & OMETS 2024, [29-10-2024 09:13] [ Poll : Ans ]

  • 20
  • 10
  • 16
  • Can't be determined

Solution

To solve this, let's analyze the given conditions:

  1. Track Length: 900 meters.
  2. Ratio of Speeds of A and B: 3 : 7.
  3. They are running in opposite directions.

Let's break down the solution:

Step 1: Determine Individual Speeds

Since the ratio of their speeds is 3:7, we can represent A's speed as 3x3x and B's speed as 7x7x, where xx is a common multiplier.

Step 2: Relative Speed

Since they are running in opposite directions, their relative speed will be the sum of their speeds: 3x+7x=10x3x + 7x = 10x

Step 3: Time to Complete One Lap

Since they start at the same point and will meet for the first time at the starting point after both completing a full lap, we calculate the time it takes them to meet at the starting point again.

Since B's speed is faster, we’ll calculate based on the time A takes to complete the lap:

  • Total distance = 900 meters.
  • A’s speed = 3x3x, so Time=9003x=300/x\text{Time} = \frac{900}{3x} = 300/x.

Thus, both A and B will meet at the starting point after 300/x300/x seconds.

Step 4: Calculate Instances of 10m Distance

Since their relative speed is 10x10x, the time taken to have a separation of 10 meters is: Time=1010x=1x seconds\text{Time} = \frac{10}{10x} = \frac{1}{x} \text{ seconds}

Within the total time of 300/x300/x seconds, the number of times A and B are at a distance of 10 meters from each other is: 300/x1/x=300\frac{300/x}{1/x} = 300

Thus, A and B will be at a distance of 10 meters from each other 300 times.

Since this answer is not in the options, let's verify if an adjustment is required based on problem constraints or typical errors in interpreting "distance times." Given the current structure, if an answer adjustment arises through simplification or clarifying meeting points only:

Conclusion: Final Answer Not Match

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Math Problem Analysis

Mathematical Concepts

Relative Speed
Ratios
Distance Calculation
Circular Motion

Formulas

Relative speed in opposite directions: sum of individual speeds
Distance = Speed × Time
Number of occurrences = Total time / Interval time

Theorems

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Suitable Grade Level

Grades 10-12