Math Problem Statement
Let A = {x : x = 4n + 1, 1 ≤ n ≤ 5, n ∈ ℕ} and B = {y : y = 2n - 3, 2 ≤ n ≤ 4, n ∈ ℕ}. The number of relations from A to B is a multiple of ________.
Solution
The problem states:
Let and . The number of relations from to is a multiple of _______.
Step-by-step solution:
-
Set A:
- .
- For different values of , we can calculate:
- Therefore, .
- The cardinality of set , denoted by , is 5.
-
Set B:
- .
- For different values of , we can calculate:
- Therefore, .
- The cardinality of set , denoted by , is 3.
-
Number of relations:
- A relation from to is a subset of the Cartesian product . The number of possible relations is the number of subsets of .
- The number of elements in is .
- The number of subsets of is (since every element of can either be included or excluded from a subset).
-
Answer:
- The number of subsets (and hence the number of relations) is .
- is a multiple of , but also it is a multiple of , , , etc.
Thus, the number of relations is a multiple of 32.
Would you like more details or have any questions?
Related questions:
- How are Cartesian products and relations defined in set theory?
- How do you calculate the number of subsets of a set with elements?
- What other mathematical problems involve relations between sets?
- Can the concept of relations be extended to non-finite sets?
- How is the concept of relations used in computer science, such as in databases?
Tip:
When working with relations between sets, it's useful to think of them as subsets of the Cartesian product and apply the principles of combinations and power sets.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Cartesian Product
Relations
Formulas
x = 4n + 1 for A
y = 2n - 3 for B
Number of relations = 2^(|A| × |B|)
Theorems
Power Set Theorem
Relation as a Subset of Cartesian Product
Suitable Grade Level
Grades 10-12