Math Problem Statement

If set A has 3 elements and set B has 2 elements, then how many relations are possible?

Solution

The question you're asking is about how many relations are possible between two sets.

Let:

  • Set AA have 3 elements.
  • Set BB have 2 elements.

Concept:

A relation from set AA to set BB is any subset of the Cartesian product A×BA \times B. The number of elements in A×BA \times B is given by the product of the number of elements in AA and BB.

Number of elements in A×B=A×B=3×2=6\text{Number of elements in } A \times B = |A| \times |B| = 3 \times 2 = 6

For each pair in A×BA \times B, there are 2 possibilities: either the pair is included in the relation, or it is not included.

Therefore, the total number of possible relations is: 2A×B=26=642^{|A \times B|} = 2^6 = 64

Answer:

The correct option is d) 64.

Would you like further details, or have any questions?

Here are five related questions to expand on this topic:

  1. What is the definition of a Cartesian product of two sets?
  2. How can we represent a relation from set AA to set BB graphically?
  3. What is the difference between a relation and a function?
  4. How would the number of possible relations change if both sets AA and BB had the same number of elements?
  5. Can a relation from set AA to set BB be a one-to-one relation?

Tip: The number of relations depends on the number of pairs in the Cartesian product of the two sets. Always remember this when calculating possible relations.

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Math Problem Analysis

Mathematical Concepts

Relations
Sets
Cartesian Products

Formulas

Number of relations = 2^(|A| * |B|)

Theorems

Cartesian Product Theorem

Suitable Grade Level

Grades 9-12