Math Problem Statement

Find the first four terms of the recursive sequence defined below. a1 = -3 and an = an-1 - n. Also, several other recursive sequence questions, including a defined sequence with f(1) = 16, determining a function for a given sequence, and finding terms of specific recursive sequences.

Solution

I see the image contains multiple math problems, specifically focused on recursive sequences and their related terms. Let me help you with each one.

Problem 6:

"Find the first four terms of the recursive sequence defined below."

  • a1=3a_1 = -3
  • an=an1na_n = a_{n-1} - n

Solution:

  • a1=3a_1 = -3
  • a2=a12=32=5a_2 = a_1 - 2 = -3 - 2 = -5
  • a3=a23=53=8a_3 = a_2 - 3 = -5 - 3 = -8
  • a4=a34=84=12a_4 = a_3 - 4 = -8 - 4 = -12

Answer: The first four terms are a1=3a_1 = -3, a2=5a_2 = -5, a3=8a_3 = -8, and a4=12a_4 = -12.

Problem 7:

"A sequence is defined recursively by f(1)=16f(1) = 16 and f(n)=f(n1)+2nf(n) = f(n-1) + 2n. Find f(4)f(4)."

Solution:

  • f(1)=16f(1) = 16
  • f(2)=f(1)+2(2)=16+4=20f(2) = f(1) + 2(2) = 16 + 4 = 20
  • f(3)=f(2)+2(3)=20+6=26f(3) = f(2) + 2(3) = 20 + 6 = 26
  • f(4)=f(3)+2(4)=26+8=34f(4) = f(3) + 2(4) = 26 + 8 = 34

Answer: f(4)=34f(4) = 34.

Problem 8:

"Find the third term in the recursive sequence an+1=2an1a_{n+1} = 2a_n - 1, where a1=3a_1 = 3."

Solution:

  • a1=3a_1 = 3
  • a2=2a11=2(3)1=61=5a_2 = 2a_1 - 1 = 2(3) - 1 = 6 - 1 = 5
  • a3=2a21=2(5)1=101=9a_3 = 2a_2 - 1 = 2(5) - 1 = 10 - 1 = 9

Answer: a3=9a_3 = 9.

Problem 9:

"Which recursively defined function represents the sequence 3, 7, 15, 31...?" Looking at the recursive pattern in the sequence:

  • 7=2(3)+17 = 2(3) + 1
  • 15=2(7)+115 = 2(7) + 1
  • 31=2(15)+131 = 2(15) + 1

Answer: Option 3: f(1)=3,f(n+1)=2f(n)+1f(1) = 3, \, f(n+1) = 2f(n) + 1.

Problem 10:

"What is the fourth term of the sequence defined by a1=3xy5a_1 = 3xy^5 and an=(2xy)an1a_n = \left( \frac{2x}{y} \right) a_{n-1}?"

Solution: Start with a1=3xy5a_1 = 3xy^5.

  • a2=(2xy)a1=2xy×3xy5=6x2y4a_2 = \left( \frac{2x}{y} \right) a_1 = \frac{2x}{y} \times 3xy^5 = 6x^2y^4
  • a3=(2xy)a2=2xy×6x2y4=12x3y3a_3 = \left( \frac{2x}{y} \right) a_2 = \frac{2x}{y} \times 6x^2y^4 = 12x^3y^3
  • a4=(2xy)a3=2xy×12x3y3=24x4y2a_4 = \left( \frac{2x}{y} \right) a_3 = \frac{2x}{y} \times 12x^3y^3 = 24x^4y^2

Answer: The fourth term is 24x4y224x^4y^2, which corresponds to Option 3.


Would you like further details on any of these solutions, or do you have additional questions? Here are 5 related questions:

  1. How would the recursive formula change if the sequence in problem 6 was defined as an=an1+na_n = a_{n-1} + n?
  2. What is the general formula for the sequence defined in problem 7?
  3. How would the solution to problem 9 change if the sequence started with 5 instead of 3?
  4. Could the formula for problem 10 work for negative exponents in a1a_1?
  5. How would the solution to problem 8 change if a1a_1 was 4 instead of 3?

Tip: When working with recursive sequences, calculating a few initial terms helps to identify patterns and verify formulas.

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Math Problem Analysis

Mathematical Concepts

Recursive Sequences
Arithmetic Progressions
Geometric Progressions

Formulas

an = an-1 - n
f(n) = f(n-1) + 2n
f(n+1) = 2f(n) + 1
an = (2x/y) * a(n-1)

Theorems

Recursive Definitions
Arithmetic Series Theorem
Geometric Series Theorem

Suitable Grade Level

Grades 9-12