Math Problem Statement

Pola bilangan: 6, 12, 20, … adalah… Pola bilangan: 3, 5, 8, 13, 55, … adalah… Niai * dan y dari pola bilangan 1, 3, 5, 7, 9, 11, p, q adalah… Nilai x dari barisan bilangan 9, 16, 36, 49, 81, … adalah… Nilai x dari barisan bilangan 1/1, 1/8, 1/27, 1/64, 1/125, x adalah…

Solution

The image you uploaded appears to be a math problem sheet in Indonesian. The questions seem to focus on identifying patterns in sequences, calculating values based on series, and choosing the correct answers from multiple-choice options. Let's go through each question and solve them.


Question 1:

"Pola bilangan: 6, 12, 20, … adalah…" This is asking for the continuation of the sequence.

Looking at the pattern:

  • 126=612 - 6 = 6
  • 2012=820 - 12 = 8

The differences between consecutive terms increase by 2.

To continue the sequence:

  • Next term: 20+10=3020 + 10 = 30
  • Then: 30+12=4230 + 12 = 42

The answer is 30 and 42.

Question 2:

"Pola bilangan: 3, 5, 8, 13, 55, … adalah…" This sequence seems to be increasing in a non-linear way.

Looking at the differences between consecutive terms:

  • 53=25 - 3 = 2
  • 85=38 - 5 = 3
  • 138=513 - 8 = 5
  • 5513=4255 - 13 = 42

The pattern is inconsistent, so there seems to be a misunderstanding or typo in the sequence. If the sequence followed a predictable pattern, I'd be able to provide the continuation.


Question 3:

"Niai * dan y dari pola bilangan 1, 3, 5, 7, 9, 11, p, q adalah…"

This sequence appears to increase by 2. Therefore:

  • p=13p = 13
  • q=15q = 15

The answer is 13 and 15.


Question 4:

"Nilai x dari barisan bilangan 9, 16, 36, 49, 81, … adalah…"

This sequence involves squares of integers:

  • 9=329 = 3^2
  • 16=4216 = 4^2
  • 36=6236 = 6^2
  • 49=7249 = 7^2
  • 81=9281 = 9^2

The missing number seems to be 52=255^2 = 25.

Answer: 25 and 64.


Question 5:

"Nilai x dari barisan bilangan 11,18,127,164,1125,x\frac{1}{1}, \frac{1}{8}, \frac{1}{27}, \frac{1}{64}, \frac{1}{125}, x adalah…"

This sequence is the reciprocal of cube numbers:

  • 1=131 = 1^3
  • 8=238 = 2^3
  • 27=3327 = 3^3
  • 64=4364 = 4^3
  • 125=53125 = 5^3

The next cube is 63=2166^3 = 216, so the next term is 1216\frac{1}{216}.

Answer: 1216\frac{1}{216}.


Let me know if you'd like detailed explanations on any of these problems!


Related Questions:

  1. What is the general formula for finding terms in an arithmetic progression?
  2. How do you identify the next term in a geometric sequence?
  3. Can all sequences be expressed as a function of nn? Why or why not?
  4. What is the difference between arithmetic and geometric progressions?
  5. How can patterns in non-numeric sequences be analyzed?

Tip:

When dealing with sequences, always check for constant differences (arithmetic) or ratios (geometric) between terms.

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Math Problem Analysis

Mathematical Concepts

Number Sequences
Arithmetic Progression
Geometric Progression
Patterns in Sequences

Formulas

Arithmetic progression: a_n = a_1 + (n-1) * d
Geometric progression: a_n = a_1 * r^(n-1)

Theorems

Properties of arithmetic and geometric progressions

Suitable Grade Level

Grades 7-9