To find $f(6)$, we need to use the recursive relationship provided:

• $f(1) = 8$
• $f(n) = f(n-1) + 4$ for $n > 1$

Step-by-step Calculation:

1. Given: $f(1) = 8$
2. Find $f(2)$: $f(2) = f(1) + 4 = 8 + 4 = 12$
3. Find $f(3)$: $f(3) = f(2) + 4 = 12 + 4 = 16$
4. Find $f(4)$: $f(4) = f(3) + 4 = 16 + 4 = 20$
5. Find $f(5)$: $f(5) = f(4) + 4 = 20 + 4 = 24$
6. Find $f(6)$: $f(6) = f(5) + 4 = 24 + 4 = 28$

Final Answer:

$f(6) = 28$

Would you like further clarification on any step?

Here are 5 questions based on this solution:

1. What is the recursive function formula used here?
2. Can you find $f(7)$ using the same method?
3. How would the function change if the increment was 5 instead of 4?
4. Can you generalize the function for $f(n)$?
5. How does recursion help in defining functions like this?

Tip: Recursive formulas break down a problem into smaller instances, simplifying complex calculations.