We are given the function $f(n)$ defined as follows:

$f(1) = 6$

$f(n) = f(n-1) - 3 \text{ for } n > 1$

We need to find the value of $f(5)$.

Step 1: Calculate $f(2)$

$f(2) = f(1) - 3 = 6 - 3 = 3$

Step 2: Calculate $f(3)$

$f(3) = f(2) - 3 = 3 - 3 = 0$

Step 3: Calculate $f(4)$

$f(4) = f(3) - 3 = 0 - 3 = -3$

Step 4: Calculate $f(5)$

$f(5) = f(4) - 3 = -3 - 3 = -6$

Thus, the value of $f(5)$ is $\boxed{-6}$.

Would you like more details or have any questions? Here are 5 related questions to consider:

1. What would be the value of $f(6)$?
2. How can you generalize the function $f(n)$ for any $n$?
3. How would the function change if $f(n) = f(n-1) - k$ where $k$ is a constant?
4. What if $f(1)$ was a different value? How would that affect $f(5)$?
5. Can you derive a direct formula for $f(n)$ without calculating step by step?

Tip: For functions defined recursively, try to identify a pattern or relation to simplify calculations for larger $n$.