Let z

To calculate the real part of $z = 1 - \frac{1}{i}$, we first simplify the expression.

1. Begin by rewriting $\frac{1}{i}$ in a more manageable form: $\frac{1}{i} = \frac{1}{i} \times \frac{i}{i} = \frac{i}{-1} = -i$

   So, the expression for $z$ becomes: $z = 1 - (-i) = 1 + i$

2. Now, the real part of $z$, denoted as $\text{Re}(z)$, is simply the real number part of $z$.

Thus, the real part of $z = 1 + i$ is: $\text{Re}(z) = 1$

Would you like more details or have any questions?

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Here are five related questions:

1. What is the imaginary part of $z$?
2. How do you represent $z = 1 + i$ in polar form?
3. What is the modulus (absolute value) of $z = 1 + i$?
4. Can you compute the argument (angle) of $z$ in radians?
5. How would you square $z = 1 + i$?

Tip: When dividing by $i$, multiply by $i/i$ to get rid of the imaginary unit in the denominator.