Math Problem Statement

Which of the following statements are true for all z ≠ 0? 1. z + z* is real 2. z - z* is real 3. zz* is real 4. z / z* is real

Solution

Let's break down each of the given statements to determine which are true for any non-zero complex number zz.

Let zz be a complex number. A complex number zz can be expressed in the form:

z=x+iyz = x + iy

where xx and yy are real numbers and ii is the imaginary unit (i2=1i^2 = -1). The complex conjugate zz^* of zz is defined as:

z=xiyz^* = x - iy

Now, let's analyze each statement:

1. z+zz + z^* is real:

z+z=(x+iy)+(xiy)=2xz + z^* = (x + iy) + (x - iy) = 2x Since 2x2x is a real number (as xx is real), this statement is true.

2. zzz - z^* is real:

zz=(x+iy)(xiy)=2iyz - z^* = (x + iy) - (x - iy) = 2iy Since 2iy2iy is purely imaginary, this statement is false.

3. zzzz^* is real:

zz=(x+iy)(xiy)=x2(iy)2=x2+y2zz^* = (x + iy)(x - iy) = x^2 - (iy)^2 = x^2 + y^2 The result, x2+y2x^2 + y^2, is always real (it’s the modulus squared of zz), so this statement is true.

4. zz\frac{z}{z^*} is real:

zz=x+iyxiy\frac{z}{z^*} = \frac{x + iy}{x - iy} Multiplying numerator and denominator by the conjugate of the denominator:

zz=(x+iy)(x+iy)(xiy)(x+iy)=x2+2ixyy2x2+y2\frac{z}{z^*} = \frac{(x + iy)(x + iy)}{(x - iy)(x + iy)} = \frac{x^2 + 2ixy - y^2}{x^2 + y^2} This simplifies to a complex number unless y=0y = 0 (i.e., unless zz is real). Since it’s not always real, this statement is false.

Final Conclusion:

  • z+zz + z^* is real: True
  • zzz - z^* is real: False
  • zzzz^* is real: True
  • zz\frac{z}{z^*} is real: False

Would you like a further breakdown or have any questions? Here are some related questions for further practice:

  1. What is the geometric interpretation of zz and zz^* in the complex plane?
  2. How is the modulus of a complex number zz related to zzzz^*?
  3. Can zzz - z^* ever be zero, and if so, under what conditions?
  4. What does the result zz\frac{z}{z^*} represent geometrically?
  5. How can you find the real and imaginary parts of zz using z+zz + z^* and zzz - z^*?

Tip: For any complex number zz, the product zzzz^* is always the square of the modulus of zz, a useful fact in many calculations.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Conjugates
Real and Imaginary Parts

Formulas

z + z* = 2x
z - z* = 2iy
zz* = x^2 + y^2
z / z* = (x + iy) / (x - iy)

Theorems

Properties of complex conjugates
Modulus of a complex number

Suitable Grade Level

Undergraduate/Advanced High School