Math Problem Statement

Let $z$ and $w$ be complex numbers such that $|z| = |w| = 1$ and $zw \ne -1.$

(a) Prove that $\overline{z} = \frac{1}{z}$ and $\overline{w} = \frac{1}{w}.$

(b) Prove that $\frac{z + w}{zw + 1}$ is a real number.

Solution

Let's address the problem step by step.

Part (a): Prove that z=1z\overline{z} = \frac{1}{z} and w=1w\overline{w} = \frac{1}{w}.

We are given that zz and ww are complex numbers such that z=w=1|z| = |w| = 1, meaning both numbers lie on the unit circle in the complex plane. The modulus of a complex number zz is given by z=zz|z| = \sqrt{z\overline{z}}, and since z=1|z| = 1, this gives: z2=zz=1.|z|^2 = z\overline{z} = 1. Thus, we can solve for z\overline{z}: z=1z.\overline{z} = \frac{1}{z}. Similarly, for ww, we have: w2=ww=1,|w|^2 = w\overline{w} = 1, so w=1w.\overline{w} = \frac{1}{w}. This proves part (a).


Part (b): Prove that z+wzw+1\frac{z + w}{zw + 1} is a real number.

To show that z+wzw+1\frac{z + w}{zw + 1} is real, we need to demonstrate that the imaginary part of this expression is zero.

We will use the fact that z=1z\overline{z} = \frac{1}{z} and w=1w\overline{w} = \frac{1}{w}, as well as the property of conjugates that for a complex number zz, if zz is real, then z=z\overline{z} = z.

The conjugate of the expression z+wzw+1\frac{z + w}{zw + 1} is given by: (z+wzw+1)=z+wzw+1.\overline{\left( \frac{z + w}{zw + 1} \right)} = \frac{\overline{z + w}}{\overline{zw + 1}}. Using the properties of conjugation, we can distribute the conjugate over the sum and product: z+w=z+w=1z+1w,\overline{z + w} = \overline{z} + \overline{w} = \frac{1}{z} + \frac{1}{w}, and zw+1=zw+1=zw+1=1z1w+1=1zw+1.\overline{zw + 1} = \overline{zw} + \overline{1} = \overline{z} \cdot \overline{w} + 1 = \frac{1}{z} \cdot \frac{1}{w} + 1 = \frac{1}{zw} + 1. Thus, the conjugate of the expression becomes: 1z+1w1zw+1.\frac{\frac{1}{z} + \frac{1}{w}}{\frac{1}{zw} + 1}. Now, simplify 1z+1w\frac{1}{z} + \frac{1}{w} and 1zw+1\frac{1}{zw} + 1: 1z+1w=w+zzw,\frac{1}{z} + \frac{1}{w} = \frac{w + z}{zw}, and 1zw+1=1+zwzw.\frac{1}{zw} + 1 = \frac{1 + zw}{zw}. Substitute these into the conjugate expression: (z+wzw+1)=z+wzw1+zwzw=z+w1+zw.\overline{\left( \frac{z + w}{zw + 1} \right)} = \frac{\frac{z + w}{zw}}{\frac{1 + zw}{zw}} = \frac{z + w}{1 + zw}. This shows that: (z+wzw+1)=z+wzw+1.\overline{\left( \frac{z + w}{zw + 1} \right)} = \frac{z + w}{zw + 1}. Since the expression equals its conjugate, it must be a real number.

Thus, we have shown that z+wzw+1\frac{z + w}{zw + 1} is a real number, which completes the proof of part (b).


Would you like more details or further explanation?

Here are 5 questions to further explore related topics:

  1. What are the properties of complex conjugates on the unit circle?
  2. How do conjugation and modulus relate to real and imaginary parts of complex numbers?
  3. What conditions must hold for a complex fraction to be real?
  4. How can we interpret the geometric meaning of z=1|z| = 1 in the complex plane?
  5. Can you generalize the result to other complex functions of two variables?

Tip: When working with complex numbers, conjugates and moduli are essential tools to manipulate and simplify expressions, particularly when dealing with unit circle properties.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Conjugates
Modulus
Real and Imaginary Parts

Formulas

$|z|^2 = z\overline{z} = 1$
$\overline{z} = \frac{1}{z}$
$\overline{\left(\frac{z + w}{zw + 1}\right)} = \frac{z + w}{zw + 1}$

Theorems

Modulus of Complex Numbers
Properties of Conjugates
Real Number Condition

Suitable Grade Level

Undergraduate level