Math Problem Statement

The archway of the main entrance of a university is modeled by the quadratic equation y = -x2 + 6x. The university is hanging a banner at the main entrance at an angle defined by the equation 4y = 21 − x. At what points should the banner be attached to the archway? A. (1.5,5.62) and (3.5,6.12) B. (1.5,4.87) and (3.5,4.37) C. (1,5.5) and (5.25,6.56) D. (1,5) and (5.25,3.94)

Solution

To determine where the banner should be attached to the archway, we need to find the points where the two equations intersect. The equations represent two curves: the archway and the banner.

We are given the two equations:

  1. The archway: y=x2+6xy = -x^2 + 6x
  2. The banner: 4y=21x4y = 21 - x (which can be rewritten as y=21x4y = \frac{21 - x}{4})

To find the points of intersection, we substitute the expression for yy from the second equation into the first equation.

Step 1: Substitute y=21x4y = \frac{21 - x}{4} into y=x2+6xy = -x^2 + 6x

21x4=x2+6x\frac{21 - x}{4} = -x^2 + 6x

Step 2: Eliminate the fraction by multiplying both sides of the equation by 4

21x=4(x2+6x)21 - x = 4(-x^2 + 6x) 21x=4x2+24x21 - x = -4x^2 + 24x

Step 3: Rearrange the terms into a standard quadratic form

4x225x+21=04x^2 - 25x + 21 = 0

Step 4: Solve the quadratic equation using the quadratic formula

The quadratic formula is given by: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} For the equation 4x225x+21=04x^2 - 25x + 21 = 0, the coefficients are:

  • a=4a = 4
  • b=25b = -25
  • c=21c = 21

Now, applying the quadratic formula: x=(25)±(25)24(4)(21)2(4)x = \frac{-(-25) \pm \sqrt{(-25)^2 - 4(4)(21)}}{2(4)} x=25±6253368x = \frac{25 \pm \sqrt{625 - 336}}{8} x=25±2898x = \frac{25 \pm \sqrt{289}}{8} x=25±178x = \frac{25 \pm 17}{8}

Step 5: Find the two possible values for xx

x1=25+178=428=5.25x_1 = \frac{25 + 17}{8} = \frac{42}{8} = 5.25 x2=25178=88=1x_2 = \frac{25 - 17}{8} = \frac{8}{8} = 1

Step 6: Find the corresponding yy-values

Now substitute these xx-values back into either equation to find the corresponding yy-values. Let's use the equation y=21x4y = \frac{21 - x}{4}.

For x1=5.25x_1 = 5.25: y=215.254=15.754=3.9375y = \frac{21 - 5.25}{4} = \frac{15.75}{4} = 3.9375

For x2=1x_2 = 1: y=2114=204=5y = \frac{21 - 1}{4} = \frac{20}{4} = 5

Step 7: Conclusion

The points where the banner should be attached are approximately:

  • (1,5)(1, 5)
  • (5.25,3.94)(5.25, 3.94)

Thus, the correct answer is D. (1, 5) and (5.25, 3.94).

Would you like more details on any step or further clarification on how the quadratic equation was solved?

Additional Questions:

  1. How does the quadratic formula work for solving equations?
  2. What are the different ways to graph a quadratic equation?
  3. How do you check if your solution to a system of equations is correct?
  4. What is the significance of the discriminant in a quadratic equation?
  5. How do the coefficients in a quadratic equation affect its graph?

Tip: Always check your solutions by substituting the xx-values back into both original equations to ensure the points are valid intersections.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Systems of Equations
Solving Quadratic Equations

Formulas

Quadratic formula x = (-b ± √(b² - 4ac)) / 2a
Substitution method for solving systems of equations

Theorems

Quadratic formula
Intersection of two curves

Suitable Grade Level

Grades 9-11