Math Problem Statement

The table below shows the first few terms of a sequence. This sequence can be described by a quadratic function, where f(n) represents the nth term of the sequence. Write the quadratic function that describes the sequence. Given terms of the sequence are: f(1) = 2, f(2) = 6, f(3) = 12, f(4) = 20, f(5) = 30.

Solution

To determine the quadratic function f(n)=an2+bn+cf(n) = an^2 + bn + c that describes the given sequence, we can follow these steps:

Step 1: Identify Patterns

Let's look at the given terms of the sequence:

  • f(1)=2f(1) = 2
  • f(2)=6f(2) = 6
  • f(3)=12f(3) = 12
  • f(4)=20f(4) = 20
  • f(5)=30f(5) = 30

Step 2: Set Up Equations for Known Points

Since we know that f(n)=an2+bn+cf(n) = an^2 + bn + c, we can substitute each term to create equations:

  1. For n=1n = 1:
    a(1)2+b(1)+c=2a+b+c=2a(1)^2 + b(1) + c = 2 \quad \Rightarrow \quad a + b + c = 2

  2. For n=2n = 2:
    a(2)2+b(2)+c=64a+2b+c=6a(2)^2 + b(2) + c = 6 \quad \Rightarrow \quad 4a + 2b + c = 6

  3. For n=3n = 3:
    a(3)2+b(3)+c=129a+3b+c=12a(3)^2 + b(3) + c = 12 \quad \Rightarrow \quad 9a + 3b + c = 12

Step 3: Solve the System of Equations

Now we have a system of three equations:

  1. a+b+c=2a + b + c = 2
  2. 4a+2b+c=64a + 2b + c = 6
  3. 9a+3b+c=129a + 3b + c = 12

Subtract equation (1) from equation (2):

(4a+2b+c)(a+b+c)=62(4a + 2b + c) - (a + b + c) = 6 - 2 3a+b=43a + b = 4

Now subtract equation (2) from equation (3):

(9a+3b+c)(4a+2b+c)=126(9a + 3b + c) - (4a + 2b + c) = 12 - 6 5a+b=65a + b = 6

Now we have two equations with two variables:

  1. 3a+b=43a + b = 4
  2. 5a+b=65a + b = 6

Subtract the first equation from the second:

(5a+b)(3a+b)=64(5a + b) - (3a + b) = 6 - 4 2a=2a=12a = 2 \quad \Rightarrow \quad a = 1

Substitute a=1a = 1 into 3a+b=43a + b = 4:

3(1)+b=4b=13(1) + b = 4 \quad \Rightarrow \quad b = 1

Finally, substitute a=1a = 1 and b=1b = 1 into a+b+c=2a + b + c = 2:

1+1+c=2c=01 + 1 + c = 2 \quad \Rightarrow \quad c = 0

Step 4: Write the Quadratic Function

The quadratic function that describes the sequence is:

f(n)=n2+nf(n) = n^2 + n

Verification

Let's verify by plugging in the values of nn:

  • f(1)=12+1=2f(1) = 1^2 + 1 = 2
  • f(2)=22+2=6f(2) = 2^2 + 2 = 6
  • f(3)=32+3=12f(3) = 3^2 + 3 = 12
  • f(4)=42+4=20f(4) = 4^2 + 4 = 20
  • f(5)=52+5=30f(5) = 5^2 + 5 = 30

This matches the sequence, confirming that the function is correct.


Would you like further details on any part of this solution?

Here are some related questions you might find helpful:

  1. How do you determine if a sequence can be represented by a quadratic function?
  2. What are the steps to solve a system of equations for quadratic sequences?
  3. How can you identify the pattern in sequences that aren't quadratic?
  4. Can this method be used for higher-order polynomial sequences?
  5. How does changing coefficients in a quadratic function affect its shape?

Tip: For sequences, check the first and second differences of terms to identify if it's quadratic (constant second difference).

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Math Problem Analysis

Mathematical Concepts

Quadratic Sequences
System of Equations
Patterns in Sequences

Formulas

Quadratic formula: f(n) = an^2 + bn + c

Theorems

Sequence patterns and quadratic formula application

Suitable Grade Level

Grade 10