Math Problem Statement

Prove the precise definition for each limit statement lim(x^2+5x-5)=9

Solution

To prove a precise definition of the limit statement:

limx2(x2+5x5)=9,\lim_{x \to 2} (x^2 + 5x - 5) = 9,

we'll use the epsilon-delta definition of a limit.

Epsilon-Delta Definition of a Limit:

For every ε>0\varepsilon > 0, there exists a δ>0\delta > 0 such that if 0<x2<δ0 < |x - 2| < \delta, then f(x)9<ε|f(x) - 9| < \varepsilon.

Here, the function is f(x)=x2+5x5f(x) = x^2 + 5x - 5, and we are proving that as xx approaches 2, f(x)f(x) approaches 9.


Step-by-Step Proof:

  1. Start with the inequality: f(x)9<ε.|f(x) - 9| < \varepsilon.

    Plug f(x)=x2+5x5f(x) = x^2 + 5x - 5 into the inequality: (x2+5x5)9=x2+5x14.|(x^2 + 5x - 5) - 9| = |x^2 + 5x - 14|.

    We want to find δ\delta such that for any ε>0\varepsilon > 0, if x2<δ|x - 2| < \delta, then x2+5x14<ε|x^2 + 5x - 14| < \varepsilon.

  2. Factor the quadratic expression: x2+5x14=(x2)(x+7).x^2 + 5x - 14 = (x - 2)(x + 7).

    Thus, we need to make sure: (x2)(x+7)<ε.|(x - 2)(x + 7)| < \varepsilon.

  3. Find bounds for x+7|x + 7|: Since we are taking x2x \to 2, we can assume that xx is close to 2. Let’s choose a small bound for δ\delta, say δ1\delta \leq 1, so that when xx is within 1 unit of 2, we have: x2<1which implies1<x<3.|x - 2| < 1 \quad \text{which implies} \quad 1 < x < 3.

    Then: 8x+710,8 \leq x + 7 \leq 10, so x+7|x + 7| is bounded by 10. Therefore, we can estimate: (x2)(x+7)<10x2.|(x - 2)(x + 7)| < 10|x - 2|.

  4. Choose δ\delta based on ε\varepsilon: To make (x2)(x+7)<ε|(x - 2)(x + 7)| < \varepsilon, we need: 10x2<ε.10|x - 2| < \varepsilon.

    Dividing both sides by 10: x2<ε10.|x - 2| < \frac{\varepsilon}{10}.

    Thus, we can choose δ=ε10\delta = \frac{\varepsilon}{10}.


Conclusion:

For any ε>0\varepsilon > 0, if we choose δ=ε10\delta = \frac{\varepsilon}{10}, then whenever x2<δ|x - 2| < \delta, it follows that f(x)9<ε|f(x) - 9| < \varepsilon. This proves that: limx2(x2+5x5)=9.\lim_{x \to 2} (x^2 + 5x - 5) = 9.


Would you like further details on any step, or have any questions?


Here are 5 related questions for deeper exploration:

  1. How does the epsilon-delta definition apply to different types of functions (e.g., linear, cubic)?
  2. Can the epsilon-delta method be used to prove limits at infinity?
  3. What is the relationship between continuity and limits using the epsilon-delta definition?
  4. How do you prove limits involving absolute value functions using epsilon-delta?
  5. What are some common misconceptions when applying the epsilon-delta definition?

Tip: Always check the range of values around the point you're approaching to simplify the bounds on your expression!

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Math Problem Analysis

Mathematical Concepts

Limits
Epsilon-Delta Definition
Quadratic Functions

Formulas

Epsilon-Delta Definition of Limit: For every ε > 0, there exists δ > 0 such that if 0 < |x - c| < δ, then |f(x) - L| < ε

Theorems

Epsilon-Delta Definition of Limits
Factorization of Quadratic Expressions

Suitable Grade Level

Grades 11-12, Introductory Calculus