It seems like you're asking to evaluate a limit involving a function. Based on what you've written, I interpret the expression as follows:

$\lim_{x \to 0} \left(5 + 5x^2\right)$

This expression involves a limit as $x \to 0$. Let's evaluate it step-by-step.

Step 1: Substitute $x = 0$ directly into the function

The function you're working with is:

$f(x) = 5 + 5x^2$

When you substitute $x = 0$:

$f(0) = 5 + 5(0)^2 = 5 + 0 = 5$

Step 2: Evaluate the limit

Since this function is continuous (there are no discontinuities or undefined points), the limit as $x \to 0$ is simply the value of the function at $x = 0$. So,

$\lim_{x \to 0} (5 + 5x^2) = 5$

Conclusion

The value of the limit is 5, not $\infty$ or $-\infty$.

Would you like any additional details or clarifications?

Related Questions:

1. What happens if you substitute $x = 0$ into a rational function?
2. How do you evaluate limits involving polynomials?
3. What is the difference between continuous and discontinuous functions?
4. How would you evaluate a limit if the function involves a square root?
5. What is L'Hopital's Rule and when is it used?

Tip:

Always check if the function is continuous at the point you're taking the limit. For polynomials, limits are straightforward to evaluate by direct substitution.