Math Problem Statement

Prove that

Prove that \frac{1}{1 + \log_a bc} + \frac{1}{1 + \log_b ac} + \frac{1}{1 + \log_c ab} = 1.

Solution

The expression in the image is:

11+logabc+11+logbac+11+logcab=1\frac{1}{1 + \log_a bc} + \frac{1}{1 + \log_b ac} + \frac{1}{1 + \log_c ab} = 1

We are tasked with proving that this equation is true.

Step-by-Step Proof:

  1. Change of base using logarithmic identities:

    We know that logabc\log_a bc can be expressed using logarithmic properties: logabc=logab+logac\log_a bc = \log_a b + \log_a c Similarly, we apply this rule for the other terms: logbac=logba+logbc\log_b ac = \log_b a + \log_b c logcab=logca+logcb\log_c ab = \log_c a + \log_c b

  2. Using the reciprocal property of logarithms:

    Recall the property: logab=1logba\log_a b = \frac{1}{\log_b a} We can use this property to simplify the expressions.

    Now apply these substitutions and simplifications to the equation step by step.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Properties of Logarithms
Algebra

Formulas

\log_a bc = \log_a b + \log_a c
\log_a b = \frac{1}{\log_b a}

Theorems

Logarithmic Properties
Reciprocal Property of Logarithms

Suitable Grade Level

Grades 10-12