Math Problem Statement

The value of log_a b log_b c log_c a is

Solution

The given expression is:

logablogbclogca\log_a b \cdot \log_b c \cdot \log_c a

We can simplify this using the property of logarithms, which is:

logab=1logba\log_a b = \frac{1}{\log_b a}

The product of the three logarithmic terms is:

logablogbclogca=1logbalogbclogca\log_a b \cdot \log_b c \cdot \log_c a = \frac{1}{\log_b a} \cdot \log_b c \cdot \log_c a

Since logba=1logab\log_b a = \frac{1}{\log_a b}, we can simplify the terms:

=logbclogca=logba= \log_b c \cdot \log_c a = \log_b a

Now, since logbalogab=1\log_b a \cdot \log_a b = 1, the overall value simplifies to:

11

Thus, the value of the given expression is 1.

Would you like more details on this? Here are 5 related questions for further exploration:

  1. How can the change of base formula for logarithms be derived?
  2. What is the importance of logarithm properties in simplifying expressions?
  3. How does the product of logarithms relate to exponents?
  4. Can logarithmic identities be extended to complex numbers?
  5. What is the difference between natural logarithms and common logarithms?

Tip: Understanding the properties of logarithms, such as the change of base rule and product rules, can help simplify complex logarithmic expressions quickly.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Logarithmic Identities
Change of Base

Formulas

log_a b = 1 / log_b a
log_a b * log_b c * log_c a

Theorems

Logarithmic Change of Base Theorem
Logarithmic Product Rule

Suitable Grade Level

Grade 10-12