Math Problem Statement
let (xn) and (yn) be bounded sequences then prove that limsup(xn + yn) <= lim (xn) + lim (yn)
Solution
To prove that , let's proceed step by step.
Step 1: Definition of
For a bounded sequence , the is defined as: Similarly, for the sequence , And for the sequence ,
Step 2: Supremum of the Sum
The supremum of the sum of two sequences satisfies the following inequality:
This inequality holds because, for each , and thus,
Step 3: Taking the Limit Superior
Now, taking the limit superior as on both sides of the inequality above, we get:
Since the limit superior of the sum is less than or equal to the sum of the limit superiors:
Conclusion
Thus, we've shown that:
This concludes the proof.
Do you want more details or have any questions?
Here are 8 related questions to further your understanding:
- What is the difference between and ?
- Can be strictly less than ?
- How would you prove a similar inequality for ?
- What happens if one of the sequences or is unbounded?
- How does this inequality relate to the sum of two convergent sequences?
- Can you give an example of sequences where the inequality is strict?
- How do and behave under multiplication of two sequences?
- Can you extend this proof to more than two sequences?
Tip: Understanding the behavior of and is crucial in real analysis, especially when dealing with sequences that do not converge.
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Math Problem Analysis
Mathematical Concepts
Real Analysis
Limit Superior
Sequence
Formulas
-
Theorems
Inequality for Lim Sup
Suitable Grade Level
Advanced Undergraduate
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