Prove ∠BAC = 90° in Triangle ABC using Perpendiculars and Power of a Point

Math Problem Statement

In triangle ABC, if AD is perpendicular to BC and AD^2 = BD × DC, prove that ∠BAC = 90°.

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Geometry
Triangles
Perpendicular
Right Angles

AD^2 = BD × DC

Pythagoras' Theorem
Right Triangle Properties
Intersecting Secants Theorem (Power of a Point)

Grades 9-12

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